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Lunna [17]
2 years ago
11

A water bottle is dropped from a plane and accelerates because of gravity. What distance did it fall during 3 seconds?

Physics
1 answer:
exis [7]2 years ago
4 0
It’d fall 29.4m or 96.46ft

Explanation:
Uhh since gravity is 9.8m/s then in three seconds it’d drop 29.4m or 96.46ft
That is assuming there isn’t a lot of wind resistance, but if you take that into account, then it’d probably be somewhere around 25m since the water bottle is going to be heavier than the wind resistance, and since we don’t know the weight of the water bottle it can’t really be calculated.

Hope this helps!
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Answer:

Decreases by $3.6 \times 10^{-3}$ times

Explanation:

The intensity of a sound is defined as the energy of the sound that is flowing in an unit time through the unit area which is in the direction that is perpendicular to the direction of the sound waves movement.

The intensity of energy is described by the inverse square law. It states that the intensity varies inversely with the distance square of the distance.

In other words, the sound intensity decreases as inversely proportional to the squared of the distance.  i.e. $\frac{1}{r^2}$

In the context when the distance was 3 m, the intensity of the sound was = $\frac{1}{9}$

But when the distance became 6 cm or 0.06 m, the sound intensity decreases by =  $\frac{1}{0.06^2}$

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Answer:

(a) 0.3778 eV

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Explanation:

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E=\frac {-13.6}{6^2}\ eV

E=-0.3778\ eV

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(b) For first orbit energy is:

E=\frac {-13.6}{1^2}\ eV

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Answer: A

<u>Explanation:</u>

NOTES:

d = 650 meters

t = 10 seconds

**********************************

v = d/t

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To learn more about Plank time:

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