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Arisa [49]
3 years ago
5

What precaution should you take while towing a trailered boat?

Physics
2 answers:
Whitepunk [10]3 years ago
6 0
There are many precautions that one must take while towing a trailered boat:

1) Always reduce the speed, when<span> you turn it.
2) Always use extra weight when you need to stop.
3) Allow proper space while cornering
4) Keep in mind this point, as you want to stop it, keep the margin of few miles as it does not come to an end at one. </span>
Leokris [45]3 years ago
5 0

The precaution you must take while towing a trailered boat includes:

  • Get the right gear
  • Securely set up the trailer
  • Take a short test drive
  • Load the boat and check safety chains
  • Take it slow while you are driving
<h2>Further Explanation</h2>

Get the right gear

Ensure you look for a trailer that will fit your tow vehicle. Don’t overload the trailer and don’t use a boat that doesn’t fit the trailer. Before you move, ensure you read the towing ability and pay utmost attention to your tow rating; your vehicle’s curb rate and some other important things.

Securely set up the trailer

Once you get a trailer that fit in, ensure your truck hitch is securely bolted to the frame and ensure you inspect it carefully before you hook up the trailer. Inspect the all tires to be sure they are all in good conditions.

Soon as you hook up the trailer, ensure you use the safety chains. It is important that you hook up the trailer lights so that cars behind you can see you clearly while applying the brake or turning.

Take a short test drive

It is important to drive your trailer a short stretch so that you can be able to confirm that if trailer brakes work properly, and the lights work correctly.  

Load the boat and check safety chains

Take a second look at your trailer and boat to check for safety chains, latches and light plugs, and once you have carefully gotten through the steps, then you can load your boat, tie it properly and start driving.  

Take it slow while you are driving

Don’t be in haste while towing your boat. Take it slow. Use your inner and outside mirror to observe what going on behind you and apply the brakes where necessary. When you finally gets to your destination, ensure you check your boat and the trailer to make sure everything held up during transport.

LEARN MORE:

  • towing an outboard boat brainly.com/question/4080255

KEYWORDS:

  • trailered boat
  • boat
  • precaution
  • vehicle
  • mirror
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A student performing a double-slit experiment is using a green laser with a wavelength of 550 nm. She is confused when the m = 5
sweet [91]

Answer:

d = 52 μm

Explanation:

given,

wavelength of the light source (λ)= 550 nm

distance to form interference pattern(D) = 1.5 m

y = 1.6 cm = 0.016 m

width of the slits = ?

now, using displacement formula

 y = \dfrac{m\lambda\ D}{d}

for the first maxima, m = 1

 d = \dfrac{1\times \lambda\ D}{y}

 d = \dfrac{1\times  550 \times 10^{-9}\times 1.5}{0.016}

       d = 5.2 x 10⁻⁶ m

       d = 52 μm

hence, the width of her slits is equal to d = 52 μm

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3 years ago
Rogue waves are created along the "Wild Coast" off the southeast coast of ________, where the Agulhas Current flows directly aga
Vedmedyk [2.9K]

Answer:

Africa

Explanation:

A rogue wave refers to the wave that is twice the height of a significant wave occurring in a particular area. The significant wave height is generally referred to as the mean of the largest one-third of waves existing at a particular time period. In simple words, a rogue wave is much larger than any other waves that occur at the proximity of the same time.

This rough wave describes the interaction between the ocean and sea current and swelling of waves. It takes place when the large swells in the ocean, also known as the Antarctic storms, strikes with the rapidly traveling Agulhas current, and the curved water current focuses on the energy of the waves.

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3 years ago
Which of the following gases are typically used for colorful lighting when an electric current is apllied
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8 0
3 years ago
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Two uniform, solid cylinders of radius R and total mass M are connected along their common axis by a short, light rod and rest o
sveta [45]

Explanation:

A) To prove the motion of the center of mass of the cylinders is simple harmonic:

System diagram for given situation is shown in attached Fig. 1

We can prove the motion of the center of mass of the cylinders is simple harmonic if

a_{x} = -\omega^{2}  x

where aₓ is acceleration when attached cylinders move in horizontal direction:

<h3>PROOF:</h3>

rotational inertia for cylinders  is given as:

                                  I=\frac{1}{2}MR^{2} -----(1)

Newton's second law for angular motion is:

                                             ∑τ = Iα ------(2)

For linear motion in horizontal direction it is:

                                             ∑Fₓ = Maₓ ------ (3)

By definition of torque:

                                               τ  = RF --------(4)        

Put (4) and (1) in (2)

                                       RF=\frac{1}{2}MR^{2}\alpha

                                       RF=\frac{1}{2}MR^{2}\alpha

from Fig 3 it can be seen that fs is force by which the cylinders roll without slipping as they oscillate

So above equation becomes

                                   f_{s}=\frac{1}{2}MR\alpha------ (5)

As angular acceleration is related to linear by:

                                          a= R\alpha

Eq (5) becomes

                                    f_{s}=\frac{1}{2}Ma_{x}---- (6)

aₓ shows displacement in horizontal direction

From (3)

                                              ∑Fₓ = Maₓ

Fₓ is sum of fs and restoring force that spring exerts:

                                  \sum F_{x} = f_{s} - kx ----(7)

Put (7) in (3)

                                  f_{s} - kx  = Ma_{x}[/tex] -----(8)

Using (6) in (8)

                               \frac{1}{2}Ma_{x} - kx =Ma_{x}

                                     a_{x} = \frac{2k}{3M} x --- (9)

For spring mass system

                                  a= -\omega^{2} x ----- (10)

Equating (9) and (10)

                                  \omega^{2} = \frac{2k}{3M}

\omega = \sqrt{ \frac{2k}{3M}}

then (9) becomes

                                a_{x} = - \omega^{2}x

(The minus sign says that x and  aₓ  have opposite directions as shown in fig 3)

This proves that the motion of the center of mass of the cylinders is simple harmonic.

<h3 /><h3>B) Time Period</h3>

Time period is related to angular frequency as:

                                   T=\frac{2\pi }{\omega}

                                  T = 2\pi \sqrt{\frac{3M}{2k}

                           

 

5 0
3 years ago
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