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3 years ago

If you had done the experiment hands-on and the environmental air pressure changed, how would your results have been affected?

Chemistry

1 answer:

lukranit [14]3 years ago

8 0

Boyle's law states the relationship between pressure and volume of a gas.

From Boyle's law, we know that volume and pressure of a given mass of gas are inversely proportional to each other. Hence, PV = k.

Now, in carrying out this experiment, the atmospheric pressure is assumed to be constant. If the atmospheric pressure changes during the experiment, here would have been a change in the measurements of balloon volume because air pressure changes would have interfered with the results.

Learn more about Boyle's law: brainly.com/question/1437490

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How many atoms are in c6h4c12

Mekhanik [1.2K]

Answer:

their are a it is in the chemicle

Explanation:18 carbon and 4 hydrogen

so it is a toatle of 22 atoms

6 0

3 years ago

Which finding would have disproved Virchow’s hypothesis?

Svetllana [295]

D is the correct answer!! good luck!!

6 0

3 years ago

Read 2 more answers

1. A gas having the following composition is burnt under a boiler with 50% excess air.

jeka94

The composition of the stack gas are :

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of $CH_4$ : 70% of 100 g = 70 g

Mass of $C_3H_8$ : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of $CH_4$ : $\frac{70 g}{16.04 g/mol}$ = 4.3 mole

Number of moles of $C_3H_8$ : $\frac{15 g}{144.1 g/mol}$ = 0.10 mole

Mass of CO : $\frac{15 g}{28.01 g/mol}$ = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of $CH_4$ : $\frac{4.3}{4.935}$ = 0.8713

Mole fraction of $C_3H_8$ : $\frac{0.10}{4.935}$ = 0.0202

Mole fraction of CO : $\frac{0.53}{4.935}$ = 0.107

Hence, composition of the stack gas are:

$CH_4$ = 0.8713

$C_3H_8$ = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

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8 0

3 years ago

HELP ASAP!!

Ksju [112]

109/8.56=12.7
50+12.7
V=62.7

Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer

4 0

3 years ago

Read 2 more answers

1) If 0.193 grams of toluene is dissolved in 2.532 grams of p-xylene, what is the molality of toluene in the solution?2) If a fr

AveGali [126]

Answer:

The value of $K_f$ for xylene is 4.309°C/m.