<span>"prevent the engine from over speeding the armature"
hopes this help :) :D :)</span>
In the given equation :
If three physical quantities is to be added or subtracted, they must have same dimensions.
So, dimension of y = dimension of c(t²)
And we already know,
- y = M⁰L¹T⁰ [ since it represents distance/length ]
- t = M⁰L⁰T¹ [ since it represents time ]
( by squaring )
Now, we need to calculate dimension and unit of c :
Now, we got the dimension of c as :
So, it's SI unit will be :
[ since SI unit of length/distance = m, and SI unit of Time = sec, hence SI unit of T² = s² ]
Answer:
Explanation:
let the velocity of throw is u .
Time to reach horizontally .25 m is equal to reach .45 m vertically
t = .25 / u cos63
= .55 / u
For vertical motion
- h = - ut + 1/2 gt²
-.45 = -usin63 x .55 / u + .5 x9.8 (.55 / u )²
-.45 = - .49 + 1.48 / u²
.04 = 1.48 / u²
u² = 37
u = 6.08 m /s