Answer:
Margin of error = 4.21 ounces
Step-by-step explanation:
According to the Question,
- Given That, You measure 25 turtles' weights, and find they have a mean weight of 31 ounces. Assume the population standard deviation is 12.8 ounces
Therefore, Sample mean = 31 ounces , Sample size(n) = 25 , Alpha(α) = 0.10 & Population standard deviation(σ) = 12.8 ounces
- Thus, Margin of error =
× σ / √n (
at α=.010 is 1.645)
Putting The Values, We get
1.645 × (12.8 / √25 ) ⇒ 4.2112 ≈ 4.21
Thus, the maximum margin of error associated with a 90% confidence interval for the true population mean turtle weight is 4.21 ounces
A9x) = x^2 - 6x + 9 = (x - 3)^2
length of a side = x - 3
The answer is 2 in 20 or 1 in 10, all you have to do is add up the total number of marbles and then have the number of yellow in the total. So 2 in 20. Hope this helps you!
Answer:
1) 2.3
2) 4.088
3) .416
4) 12.52
5) 1012.5
Step-by-step explanation:
4x-5y=3
4x-5(10)=3
4x-50=3
+50 +50
4x=53
/4 /4
x=53/4