Answer: Ok, first lest see out problem.
It says it's a Long cylindrical charge distribution, So you can ignore the border effects on the ends of the cylinder.
Also by the gauss law we know that E¨*2*pi*r*L = Q/ε0
where Q is the total charge inside our gaussian surface, that will be a cylinder of radius r and heaight L.
So Q= rho*volume= pi*r*r*L*rho
so replacing : E = (1/2)*r*rho/ε0
you may ask, ¿why dont use R on the solution?
since you are calculating the field inside the cylinder, and the charge density is uniform inside of it, you don't see the charge that is outside, and in your calculation actuali doesn't matter how much charge is outside your gaussian surface, so R does not have an effect on the calculation.
R would matter if in the problem they give you the total charge of the cylinder, so when you only have the charge of a smaller r radius cylinder, you will have a relation between r and R that describes how much charge density you are enclosing.
I think the answer is (C.) but im not sure
Answer:
Yes, the answer on <em>how far off the ground a typical truck is happens to be</em> physically realistic.
Explanation:
This concept could be explained with when someone is viewing a picture from a particular distance. The farther the person is from the picture, the smaller the details of the picture and the higher they picture would be unappriciated and vice versa.
Likewise the small truck on ground. <em>The distance off ground the truck is being viewed, the smaller the truck would become.</em>
Answer:
Hello there use something that looks like this
Explanation:
This is an accurate representation of something you are working on!
As you can see the wire and the core are represented on the left and is showing how it can be represented on your right hand and how they are similar!