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stepan [7]
3 years ago
10

You are tasked with completing the Venn diagram comparing weather

Physics
1 answer:
chubhunter [2.5K]3 years ago
8 0
Weather can be forecasted (meterologists) , climate can be forecasted scientists use computer programs called climate models. sorry im not sure about the other ones though :) Good luck on your assignments!
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a 150 kg roller coaster is released from rest at the top of a 50 m hill. how fast will it be going if the second hill is 10 m hi
pav-90 [236]

Answer:

10 m/s

Explanation:

The potential energy of the roller coaster is converted to kinetic energy. According to law of transformation of energy, potential energy = kinetic energy.

mgh = ½mv².Take g as 10m/s².

150 * 10 * 50 = ½ * 150 * v².

7500 = 75v².

v² = 7500/75.

v = √100.

v= 10 m/s.

8 0
3 years ago
Ions can cross a membrane without the help of an integral membrane protein. True or False
denis-greek [22]

Answer:

False

Explanation:

ionic particles, which are hydrophilic, cannot easily cross a membrane. Very small polar molecules, such as water, can cross via simple diffusion due to their small size. Charged atoms or molecules of any size cannot cross the cell membrane via simple diffusion as the charges are repelled. Because these ions can cross the cell membrane, their movement is restricted to protein channels and specialized transport mechanisms in the membrane.

6 0
4 years ago
You drop a rock down a well and hear a splash 3 s later. As Charlie Brown would say, the well is 3 seconds deep. How fast is the
vampirchik [111]
Since it was dropped, it should be the speed of gravity which is 9.8 meters/second
5 0
2 years ago
Scientists on Earth are able to communicate with rovers on Mars through their receivers, which can receive and process signals.
Bas_tet [7]
B electromagnetic waves I think
4 0
3 years ago
Read 2 more answers
Determine the launch speed of a horizontally launched cannonball that lands 26.3
nlexa [21]

Answer:

The cannon has an initial speed of 13.25 m/s.

Explanation:

The launched cannonball is an example of a projectile. Thus, its launch speed can be determined by the application of the formula;

R = u\sqrt{\frac{2H}{g} }

Where: R is the range of the projectile, u is its initial speed, H is the height of the cliff and g is the gravitaty.

R = 26.3 m, H = 19.3 m, g = 9.8 m/s^{2}.

So that:

26.3 = u\sqrt{\frac{2*19.3}{9.8} }

(26.3)^{2} = u^{2} x \frac{38.6}{9.8}

691.69 =  u^{2} x \frac{38.6}{9.8}

u^{2} = \frac{691.69*9.8}{38.6}

   = \frac{6778.562}{38.6}

u^{2} = 175.6104

⇒ u = \sqrt{175.6104}

  = 13.2518

u = 13.25 m/s

The initial speed of the cannon is 13.25 m/s.

4 0
3 years ago
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