Answer:
m= 10 kg a = 52 m / s²
Explanation:
For this problem we must use Newton's second law, let's apply it to each axis
X axis
F - fr = ma
The equation for the force of friction is
-fr = miu N
Axis y
N- W = 0
N = mg
Let's replace and calculate laceration
F - miu (mg) = ma
a = F / m - mi g
a = 527.018 / m - 0.17 9.8
We must know the mass of the body suppose m = 10 kg
a = 527.018 / 10 - 1,666
a = 52 m / s²
Answer: momentum has the same direction as that of velocity but when 2 bodies with the same linear momentum & different velocities it has different masses because a vector quantity is represented by a cross product of mass and velocity of object .
Answer:
4.123 * 10∧4 kg
Explanation:
mass of car M' = 3.34 * 10∧4 kg
energy loss E = 19/100 K
from law of conservation of momentum ,
M' V' = ( M' + M'' ) v
V = M' V' / ( M' + M'' )
Initial kinetic energy is K' = (M' V')² / 2
final kinetic energy K" = 81 K' /100
= (M' V')² 81 / (200) = ( M' + M'' ) v²/ 2
therefore , M' / ( M' + M" ) = 0.81
mass of caboose is , M" = 1.234 M' - M'
M" = .234 M'
= 0,234 ( 3.34 * 10∧4 kg)
= 4.123 * 10∧4 kg
