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igor_vitrenko [27]
3 years ago
9

How is it possible for two objects to have the same momentum, but different velocities?

Physics
1 answer:
coldgirl [10]3 years ago
8 0

Answer: momentum has the same direction as that of velocity but when 2 bodies with the same linear momentum & different velocities it has different masses because a vector quantity is represented by a cross product of mass and velocity of object .

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Electrostatic repulsion is the force between two charges having the same sign, that tends to separate them further. The force is proportional to the product of the charges, and inversely proportional to the square of the distance between them.
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A block lies on a frictionless floor. a force of 5 n pulls toward the east while a force of 4 n pulls toward the north. what is
sveticcg [70]

Given below the arrangement of loading on the larger boat by two tug boats.

F₁ = 5 N

F₂ = 4 N

Angle between them θ = 90⁰

Resultant between two vectors, F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\theta }

Substituting

   F = \sqrt{5^2+4^2+2*5*4*cos 90} \\ \\ = 6.403 N

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What is v^2=0.05-4.9 please i need this asap​
Margaret [11]

Answer:

v =2.02

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v^2=0.05-4.9

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v=2.02

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7 0
3 years ago
Object 1 has a momentum of 10 kg m/s and Object 2 has a momentum of 25 kg m/s. Will it be easier to change the direction of move
svetoff [14.1K]

Answer:

I think its object 1

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Two particles, one with charge -5.45 × 10^-6 C and one with charge 4.39 × 10^-6 C, are 0.0209 meters apart. What is the magnitud
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Explanation:

Given that,

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F=k\dfrac{q_1q_2}{r^2}

F=9\times 10^9\times \dfrac{-5.45\times 10^{-6}\times 4.39\times 10^{-6}}{(0.0209)^2}

F = -492.95 N

2. Distance between two identical charges, r=0.0209\ m

Electric force is given by :

F=\dfrac{kq_3^2}{r^2}

q_3=\sqrt{\dfrac{Fr^2}{k}}

q_3=\sqrt{\dfrac{492.95\times (0.0209)^2}{9\times 10^9}}

q_3=4.89\times 10^{-6}\ C

Hence, this is the required solution.

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3 years ago
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