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Alexxandr [17]
4 years ago
8

The type of bond that forms between two atoms when electrons are shared is a(n) _______________ bond.

Chemistry
1 answer:
ollegr [7]4 years ago
8 0
<span>covalent. When two atoms share valence electrons, such a type of a bond is called a covalent bond. An example of such a bond could be the H2 molecule, where two H (hydrogen) atoms share electrons in a covalent bond.</span>
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Determine the empirical formulas for compounds with the following percent compositions:
White raven [17]

Answer: a)  CS_2

b) CH_2O

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles

Moles of S=\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{1.32}{1.32}=1

For S =\frac{2.63}{1.32}=2

The ratio of C  : S = 1:2

Hence the empirical formula is CS_2

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.33}{3.33}=1

For H = \frac{6.7}{3.33}=2

For O =\frac{3.33}{3.33}=1

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is CH_2O

5 0
3 years ago
Explain why the ionization energy to remove a second electron from potassium is higher than the ionization energy to remove four
never [62]

Explanation:

It is more difficult to remove electrons from the second shell or energy level because of the imbalance between the positive nuclear charge and the remaining electrons.

  • The amount of energy required to remove electrons in ground state of an atom is the ionization energy.
  • The first ionization energy is the energy needed to remove the most loosely bound electron of an atom in the gas phase in ground state.
  • The second energy has a greater nuclear pull as it is closer to the nucleus.
  • Both potassium and silicon have the same number of energy levels.
6 0
3 years ago
Which statement names the physical property of wood
sergiy2304 [10]

Your answer is B. Rust does not rust.

3 0
3 years ago
Help!!! I don’t know how to solve!!!
ladessa [460]
Just use q=mCDeltaT

q=energy
m=mass
c=specific heat
Delta T= Change in temperature
6 0
4 years ago
A buffer solution is prepared by adding NaC2H202
olganol [36]

Shift to reactants(left)

<h3>Further explanation </h3>

A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.

The buffer solution can be acidic or basic

Acid buffer solutions consist of weak acids and their salts.  

A buffer solution of NaC2H202    and HC2H2O2 (acetic acid) is included in the acid buffer

So :

a slight addition of acid (H⁺) will be balanced by the conjugate base

the addition of a small base (OH⁻) will be balanced by the weak acid

With the addition of acid (H +), the equilibrium will shift to the left, in the formation of CH3COOH. The added acid will be neutralized by the conjugate base component (CH3COO−).

7 0
3 years ago
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