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4 years ago

The type of bond that forms between two atoms when electrons are shared is a(n) _______________ bond.

1 answer:

8 0

<span>covalent. When two atoms share valence electrons, such a type of a bond is called a covalent bond. An example of such a bond could be the H2 molecule, where two H (hydrogen) atoms share electrons in a covalent bond.</span>

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Determine the empirical formulas for compounds with the following percent compositions:

White raven [17]

Answer: a) $CS_2$

b) $CH_2O$

Explanation:

a) If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 15.8g

Mass of S= 84.2 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{15.8g}{12g/mole}=1.32moles$

Moles of S= $\frac{\text{ given mass of S}}{\text{ molar mass of S}}= \frac{84.2g}{32g/mole}=2.63moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{1.32}{1.32}=1$

For S = $\frac{2.63}{1.32}=2$

The ratio of C : S = 1:2

Hence the empirical formula is $CS_2$

b) Mass of C= 40 g

Mass of H= 6.7 g

Mass of O = 53.3 g

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40g}{12g/mole}=3.33moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.7g}{1g/mole}=6.7moles$

Moles of O = $\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{3.33}{3.33}=1$

For H = $\frac{6.7}{3.33}=2$

For O = $\frac{3.33}{3.33}=1$

The ratio of C : H: O= 1 :2: 1

Hence the empirical formula is $CH_2O$

5 0

3 years ago

Explain why the ionization energy to remove a second electron from potassium is higher than the ionization energy to remove four

never [62]

Explanation:

It is more difficult to remove electrons from the second shell or energy level because of the imbalance between the positive nuclear charge and the remaining electrons.

The amount of energy required to remove electrons in ground state of an atom is the ionization energy.
The first ionization energy is the energy needed to remove the most loosely bound electron of an atom in the gas phase in ground state.
The second energy has a greater nuclear pull as it is closer to the nucleus.
Both potassium and silicon have the same number of energy levels.

6 0

3 years ago

Which statement names the physical property of wood

sergiy2304 [10]

Your answer is B. Rust does not rust.

3 0

3 years ago

Help!!! I don’t know how to solve!!!

ladessa [460]

Just use q=mCDeltaT

q=energy
m=mass
c=specific heat
Delta T= Change in temperature

6 0

4 years ago

A buffer solution is prepared by adding NaC2H202

olganol [36]

Shift to reactants(left)

<h3>Further explanation </h3>

A buffer solution is a solution that can maintain a good pH value due to the addition of a little acid or a little base or dilution.

The buffer solution can be acidic or basic

Acid buffer solutions consist of weak acids and their salts.

A buffer solution of NaC2H202 and HC2H2O2 (acetic acid) is included in the acid buffer

So :

a slight addition of acid (H⁺) will be balanced by the conjugate base

the addition of a small base (OH⁻) will be balanced by the weak acid

With the addition of acid (H +), the equilibrium will shift to the left, in the formation of CH3COOH. The added acid will be neutralized by the conjugate base component (CH3COO−).

7 0

3 years ago