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Nadya [2.5K]
2 years ago
9

Can someone help with chemistry plz

Chemistry
1 answer:
Serhud [2]2 years ago
7 0

Answer:

ok I will sudtract and the answer is the bottom one

Explanation:

dbh

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The mole fraction of CO2 in a certain solution with H2O as the solvent is 3.6 × 10−4. What is the approximate molality of CO2 in
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Answer: C) 0.020 m

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

Molality=\frac{n\times 1000}{W_s}

where,

n = moles of solute  

W_s = weight of solvent in g  

Mole fraction of CO_2 is = 3.6\times 10^{-4} i.e.3.6\times 10^{-4}  moles of CO_2 is present in 1 mole of solution.

Moles of solute (CO_2) = 3.6\times 10^{-4}

moles of solvent (water) = 1 - 3.6\times 10^{-4} = 0.99

weight of solvent =moles\times {\text {Molar mass}}=0.99\times 18=17.82g

Molality =\frac{3.6\times 10^{-4}\times 1000}{17.82g}=0.020

Thus  approximate molality of CO_2 in this solution is 0.020 m

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3 years ago
How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature? A. 51,3
expeople1 [14]
The amount of energy released when 0.06 kg of mercury condenses at the same temperature can be calculated using its latent heat of fusion which is the opposite of melting. Latent heat of fusion and melting can be used because they have the same magnitude, but opposite signs. Latent heat is the amount of energy required to change the state or phase of a substance. For latent heat, there is no temperature change. The equation is:

E = m(ΔH)

where:
m = mass of substance
ΔH = latent heat of fusion or melting

According to data, the ΔH of mercury is approximately 11.6 kJ/kg.

E = 0.06kg (11.6 kJ/kg) = 0.696 kJ or 696 J

The answer is D. 697.08 J. Note that small differences could be due to rounding off or different data sources.
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