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yan [13]
3 years ago
13

What are the chemical properties of beryllium phosphide??

Chemistry
1 answer:
o-na [289]3 years ago
8 0

Answer:

Forms ionic bonds, insoluble, doesn't participate in single or double displacement reactions, non-reactive, high heat of combustion

Explanation:

Beryllium is a metal, since it belongs to group 2A, the alkaline earth metals. It has a total of 2 valence electrons.

Phosphorus, on the other hand, belongs to group 5A and has a total of 5 valence electrons.

We have a compound which has a metal in it, therefore, it's an ionic compound. Beryllium, our metal, loses its 2 electrons to gain an octet and phosphorus, our nonmetal, should gain 3 electrons to have an octet. The oxidation states are +2 and -3 respectively. This means we need 3 beryllium cations and 2 phosphide anions in our formula Be_3P_2.

Beryllium phosphide would be expected to be insoluble, as only beryllium chloride, fluoride, nitrate, phosphate and sulfate are soluble substances, while the remaining ones are expected to be insoluble.

Due to its insolubility, beryllium phosphide would not participate in any ionic reactions, such as single displacement or double displacement.

Since it's insoluble, we expect this compound to be chemically stable and not reactive. This implies that if we wanted to burn it, the heat of combustion would be very high, as a lot of energy would be needed to be supplied in an endothermic reaction in order to burn it.

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Select the property that is not a characteristic of an ideal recrystallization solvent.
dybincka [34]

Answer:

(C) The recrystallization solvent should be nonvolatile.

Explanation:

Recrystallization is the separation technique which is used to purify the solid compounds in their crystal or amorphous form.

Some properties follow the recrystallization process as:

The solids are more soluble in hot solvent as compared to the solubility in the cold solvent.

The solvent must have lower boiling point and can be volatile easily.

The solvent should not react with the compound.

The impurities must be soluble in the cool solvent, so that only the pure product crystallizes.

Hence, Answer - C which is not an ideal characteristic.

8 0
3 years ago
In an extraction procedure, it is advisable to: save all layers until the experiment is complete. throw away all layers as soon
LenKa [72]

All the layers should be kept until the experiment is complete.

<h3>What is extraction?</h3>

In chemistry, solvent extraction is accomplished by adding a sample containing the substance to be separated into a system of two solvents, an aqueous layer and an organic layer.

It is important to note that all the layers should be kept until the experiment is complete. No layer ought to be discarded before the work is completed.

Learn more about solvent extraction:brainly.com/question/11041092

4 0
2 years ago
The movement of charged particles cannot pass through an electrolyte to produce an electric current.
Rus_ich [418]

The movement of charged particles cannot pass through an electrolyte to produce an electric current.


True

False


FALSE

5 0
3 years ago
Calculate the ph of a 0.17 m solution of c6h5nh3no3 (kb for c6h5nh2 = 3.8 x 10-10). record your ph value to 2 decimal places.
MatroZZZ [7]
<span>Mass of the solution = 0.17m
 Kb for C6H5NH2 = 3.8 x 10^-10
 We know Ka for C6H5NH2 = 1.78x10^-11
  We have Kw = Ka x Kb => Ka = Kw / Kb
  => (C2H5NH2)(H3O^+)/(C2H5NH3^+) => 1.78x10^-11 = K^2 / 0.17
 K^2 = 3 x 10^-12 => K = 1.73 x 10^-6.
 pH = -log(Kw(H3O^+)) = -log(1.73 x 10^-6) = 5.76</span>
6 0
3 years ago
Lonic Bonding
oksano4ka [1.4K]
Na has a +1 charge, and O has a -1 charge.
3 0
3 years ago
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