Question

Calculate the mass of water produced from the reaction of 2.00 grams of hydrogen and 4.00 grams of oxygen.​

Answer 1

Answer:

              4.50 g of H₂O

Explanation:

The Balance chemical equation is

                                    2 H₂ + O₂ = 2 H₂O

Step 1: Calculate Limiting Reagent

Moles of H₂

                         Mole = 2 g / 2.02 g/mol = 0.99212 mol

Moles of O₂

                         Mole = 4 g / 32.00 g/mol = 0.125 mol

Mole ratio of H₂ : O₂ is 2 : 1. Hence, 0.99212 mol of H₂ will need 0.49606 mol of O₂. This means O₂ is limiting reagent.

Step 2: Calculate Moles of H₂O

0.125 mol of O₂ will produce 0.250 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.

Step 3: Calculate mass of H₂O

                           Mass = 0.250 mol × 18.02 g/mol = 4.50 g of H₂O