Answer:
10. True. vA = - ¼ vB
, pA = - pB
Explanation:
Let us propose the solution of this problem, as the cars are released let us use the conservation of the moment.
Initial before releasing the cars
p₀ = 0
Final after releasing cars
= mA vA + mB vB
p₀ =
0 = mA vA + mB vB
vA = - mB / mA vB
They indicate that mA = 4 mB
vA = - ¼ vB
Let's write the amount of movement for each body
pA = mA vA = 4 mB (- ¼ vB
pA = -mB vB
pB = mB vB
pA = - pB
Let's check the answers
1 False
2 False
3 False
4 false
5 False
6 False
7 False
8 False
9 False
10. True. The speed and amount of movement values are correct
Answer:
3.9 m/s
Explanation:
We are given that
Mass of car,m=
Initial velocity,u=0
Distance,s=5.9 m
Average friction force,f=
We have to find the speed of the car at the bottom of the driveway.
Net force,
Where 
Acceleration,
v=3.9 m/s
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Answer:
V = 156.85 Km/h
Explanation:
Speed of plane = 125 Km/h
angle of plane= 25° N of E
Speed of wind = 36 Km/h
angle of plane = 6° S of W
Horizontal component of the velocity
V_x = 125 cos 25° + 36 cos 6°
V_x = 149 Km/h
Vertical component of the velocity
V_y = 125 sin 25° - 36 sin 6°
V_y = 49 Km/h
Resultant of Velocity
V = 156.85 Km/h
the resulting velocity of the plane is equal to V = 156.85 Km/h
Answer:
The answer from this question is 3 m/s2.
Explanation:
8 m/s is initial velocity and 32 is final velocity. According to the rule of acceleration vf - vi we minus 8 from 32. Acceleration is the change of velocity per unit time. Then the difference (32 - 8= 24) is divided to 8. We get 3.
