D)
![2^{5+x}](https://tex.z-dn.net/?f=%202%5E%7B5%2Bx%7D%20)
Would be correct because of the properties of exponents that says when multiplying powers with the same base you can add the exponents. I don't think any of the other ones are right...
I hope this helps!
Answer:
x=-4/3y+-2/3z+2
Step-by-step explanation:
add +4y to both sides
then add -2z to both sides
then divide both sides by three
Answer:
Therefore to get 4 feet per second the values of distance and time are
![Distance = 4 feet\\Time = 1 s](https://tex.z-dn.net/?f=Distance%20%3D%204%20feet%5C%5CTime%20%3D%201%20s)
Step-by-step explanation:
Speed:
Speed is defined as the rate of distance covered in per unit time.
It is given as
It's unit is meter per second
So to get 4 feet per second
i.e Distance = 4 feet
Time = 1 second
Also we can have other values too like
Distance = 8 feet
Time = 2 second
and so on
Therefore to get 4 feet per second the values of distance and time are
![Distance = 4 feet\\Time = 1 s](https://tex.z-dn.net/?f=Distance%20%3D%204%20feet%5C%5CTime%20%3D%201%20s)
Answer:
The ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
Step-by-step explanation:
The question is:
A company knows that if it produces "x" monthly units its utility "u" could be calculated with the expression: u (x) = - 0.04x ^ 2 + 44x-4000 where "u" is expressed in dollars. Determine the ratio of the average change in profit when the level of production changes from 600 to 620 units per month. Remember that the slope of the secant line to the graph of the function represents the average rate of change.
Solution:
The expression for the utility is:
![u (x) = - 0.04x ^ {2} + 44x-4000](https://tex.z-dn.net/?f=u%20%28x%29%20%3D%20-%200.04x%20%5E%20%7B2%7D%20%2B%2044x-4000)
It is provided that the slope of the secant line to the graph of the function represents the average rate of change.
Then the ratio of the average change in profit when the level of production changes is:
![\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20change%20in%20profit%7D%3D%5Cfrac%7Bu%28x_%7B2%7D%29-u%28x_%7B1%7D%29%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
Compute the values of u (x₁) and u (x₂) as follows:
<em>x</em>₁ = 600
![u (x_{1}) = - 0.04x_{1} ^ {2} + 44x_{1}-4000](https://tex.z-dn.net/?f=u%20%28x_%7B1%7D%29%20%3D%20-%200.04x_%7B1%7D%20%5E%20%7B2%7D%20%2B%2044x_%7B1%7D-4000)
![= - 0.04(600) ^ {2} + 44(600)-4000\\=-14400+26400-4000\\=8000](https://tex.z-dn.net/?f=%3D%20-%200.04%28600%29%20%5E%20%7B2%7D%20%2B%2044%28600%29-4000%5C%5C%3D-14400%2B26400-4000%5C%5C%3D8000)
<em>x</em>₂ = 620
![u (x_{2}) = - 0.04x_{2} ^ {2} + 44x_{2}-4000](https://tex.z-dn.net/?f=u%20%28x_%7B2%7D%29%20%3D%20-%200.04x_%7B2%7D%20%5E%20%7B2%7D%20%2B%2044x_%7B2%7D-4000)
![= - 0.04(620) ^ {2} + 44(620)-4000\\=-15376+27280-4000\\=7904](https://tex.z-dn.net/?f=%3D%20-%200.04%28620%29%20%5E%20%7B2%7D%20%2B%2044%28620%29-4000%5C%5C%3D-15376%2B27280-4000%5C%5C%3D7904)
Compute the average rate of change as follows:
![\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20change%20in%20profit%7D%3D%5Cfrac%7Bu%28x_%7B2%7D%29-u%28x_%7B1%7D%29%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
![=\frac{7904-800}{620-600}\\\\=\frac{-96}{20}\\\\=-\frac{24}{5}\\\\=-24:5](https://tex.z-dn.net/?f=%3D%5Cfrac%7B7904-800%7D%7B620-600%7D%5C%5C%5C%5C%3D%5Cfrac%7B-96%7D%7B20%7D%5C%5C%5C%5C%3D-%5Cfrac%7B24%7D%7B5%7D%5C%5C%5C%5C%3D-24%3A5)
Thus, the ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
Answer:
Based off of the given information I believe the answer is 8,000,000 hydrogen atoms because it appears that the ratio between hydrogen and oxygen atoms in 2:1.
Step-by-step explanation: