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xxTIMURxx [149]
3 years ago
15

A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pr

essure is 0.600 atm. The gas is heated with a flame to a temperature of 72.4 C, what is it’s pressure at this temperature
Chemistry
1 answer:
rusak2 [61]3 years ago
3 0

Answer:

Explanation:

Given parameters:

Initial temperature T₁  = 25.2°C  = 25.2 + 273  = 298.2K

Initial pressure  = P₁  = 0.6atm

Final temperature = 72.4°C   = 72.4 + 273  = 345.4K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we use an adaption of the combined gas law where the volume gas is fixed. This simplification results into:

                  \frac{P_{1} }{T_{1} }   = \frac{P_{2} }{T_{2} }

where P and T are temperatures, 1 and 2 are initial and final temperatures.

 Input the parameters and solve;

          \frac{0.6}{298.2}   = \frac{P_{2} }{345.4}  

          P₂   = 0.7atm

         

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For the following reaction, KP = 0.455 at 945°C: At equilibrium, is 1.78 atm. What is the equilibrium partial pressure of CH4 in
Alborosie

Answer:

See explanation below

Explanation:

The question is incomplete. However, here's the missing part of the question:

<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>

<em>C(s) + 2H2(g) <--> CH4(g). </em>

<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>

With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.

The expression of Kp for this reaction is:

Kp = PpCH4 / (PpH2)²

We know the value of Kp and pressure of hydrogen, so, let's solve for CH4:

PpCH4 = Kp * PpH2²

*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.

Now solving for PpCH4:

PpCH4 = 0.455 * (1.78)²

<u><em>PpCH4 = 1.44 atm</em></u>

6 0
3 years ago
How do I find the number of moles and molar mass of Gas A and Gas B with the information provided?
drek231 [11]

Answer:

A.

Explanation:

hope this helped sorry if its wrong!

3 0
2 years ago
Heat transmits readily through this
Oksi-84 [34.3K]
Can you be more specific?

...Diamond is the best conductor of heat, but heat also transmits readily through many other substances. Do you have multiple choice?
8 0
3 years ago
5.36 litars of nitrogen gas are at :25°C and 733 mm Hg
ArbitrLikvidat [17]

Answer:

4.6L

Explanation:

Use the equation (P1*V1)/(T1)=(P2*V2)/(T2)

P= pressure

V= volume

T= temperature in kelvins (remember K= C + 273)

Convert atm to mmHg or vise versa

1.5atm*(760mmhg/1atm)= 1140mmHg

(733mmHg * 5.36L)/(298K)=(1140mmHg * V)/(402K)

V= 4.6 or 4.65L (depending on sig figs)

6 0
2 years ago
calcium is obtained industrially by electrolysis of molten cacl2 and is used in aluminum alloys. how many coulombs are needed to
Vinvika [58]

It takes 107 minutes 22 seconds and 96500 coulombs of charge produce 20.2 g of calcium.

The balanced equation for the reaction is,

CaCl _{2} \:→ \: Ca ^{ 2 + }  + 2Cl {}^{ - }

The half-reaction of calcium is,

Ca ^{2 + }  + 2e ^{ - } → \: Ca

Mass of calcium = 20.2 g

The molecular mass of calcium = 40 u.

The number of moles calcium are,

Number \: of \: moles =  \frac{mass}{molecular \: mass}

=  \frac{20.2}{40}

= 0.5 \: moles

One mole of Calcium is produced by 2 moles of electrons.

So, 0.5 moles of Calcium produce,

= 0.5 \times 2

= 1 \: mole \: of \: electron

The charge required to produce 202 g of calcium is,

=  1 \:F

= 1 \times 96500 \: C

= 96500 \: C

Current = 15 A

The time taken to produce 20.2 g of calcium is,

I  =  \frac{Q}{T}

T =  \frac{96500}{15}

= 6433.3 \: s

= 107 \: minutes \: 22 \: seconds

Therefore, 96500 columns of charge are required to produce 20.2 grams of calcium. And it takes 107 minutes and 22 seconds.

To know more about charge, refer to the below link:

brainly.com/question/14713274

#SPJ4

7 0
1 year ago
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