<h3><u>Answer</u> :</h3>
◈ As per newton's second law of motion, Force is defined as the product of mass and acceleration
Mathematically,

Unit of mass : kg
Unit of acceleration : m/s²
Therefore,
Unit of force ➠ <u>kg m/s²</u>
SI unit : <u>N (newton)</u> or <u>kg m/s²</u>
Answer:
A dekagram is thousand (1000) times larger than a centigram.
Explanation:
→ [1 dekagram = 1,000 centigrams]
→ 1 dekagram = 10 grams
→ 10 grams = 100 decigrams
→ 100 decigrams = 1,000 centigrams
Answer:
(a) Since net charge remains same,after immersion Q is same
(b) I. 14.56pF ii. 3.05V
(c) ΔU = 5.204nJ
Explanation:
a)
C = kεA/d
k=1 for air
ε is 8.85x10-12F/m
A = .0025m2
d = .125m
C = 8.85x10-12x.0025/.125 = 1.77x10-13F = 0.177pF
Q = CV = .177pF * 244V = 43.188pC
Since net charge remains same,after immersion Q is same
b)
C = kεA/d, for distilled water k is approx. 80
Cwater = Cair x k
=0.177pF x 80 = 14.16pF
Q is same and C is changed V=Q/c holds. where Q is still 43.188pC and C is now 14.16pF, so V = 43.188pC/14.16pF = 3.05V
c) Change in energy: ΔU = Uwater - Uair
Uwater = Q2/2C = (43.188)2/2x.177pF = 5.27nJ
Uair = Q2/2C = (43.188)2/2x14.16pF = 0.066nJ
ΔU = 5.204nJ
Answer:
a. 
b. 
c. 
Explanation:
Given,
*initial velocity of the ball = 
*angle of projection = \theta_i
Horizontal component of the initial velocity of the ball = 
vertical initial component of the initial velocity of the ball = 
part a
From the kinematics,
In the y-direction motion,
total vertical displacement of the ball during the whole motion is zero.
Ball is moving under the gravitational acceleration, therefore the acceleration of the ball = -g, because gravitational acceleration always acts in the downward direction,
Let t be the time of flight of the whole motion,

part b.
At the peak of the path of the ball, the vertical component of the velocity of the ball becomes zero, only horizontal component of the velocity acts on the ball is equal to = 
part c.
Initial vertical component of the velocity of the ball = 
Answer:
668 bright fringes
Explanation:
t = Thickness = 0.2 mm
= Wavelength = 600 nm
m = Number of fringes
We have the fringe width relation

So, total number of fringes will be including m = 0 is 