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irina1246 [14]
3 years ago
8

Write an equation the describes the line passing through point (0,7) with slope - 7/3

Mathematics
2 answers:
dexar [7]3 years ago
6 0

Answer:

y=\frac{7}{3}x+7

Step-by-step explanation:

y=mx+b\\\\y=\frac{7}{3}x+b\\ \\7=\frac{7}{3}(0)+b\\ \\7=b\\\\y=\frac{7}{3}x+7

velikii [3]3 years ago
4 0

For these kinds of problems, the point-slope formula comes in handy.

The point-slope form (y - y1 = m(x - x1) +b) uses the slope and a point given to find the y-intercept, or in this case, the equation of the line.

First, we plug the known #'s into the equation, then solve.

y - 7 = -7/3( x -0)

y - 7 = -7/3x

   +7        +7

y = -7/3x +7

Therefore, the equation of the line is: y = -7/3x + 7

Hope this helps!

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Answer:

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Step-by-step explanation:

y = 4x - 4 is a line with y-intercept -4 and slope 1. Both graphs A and C show that line in blue.

y = 4 is a horizontal line through y = 4. Graph A shows that line.

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The width of a rectangle is the length minus 2 units. the area of the rectangle is 35 units
Mariana [72]

Answer:

Length=7units\\\\Width=5units

Step-by-step explanation:

Width=(Length-2) units

W=(L-2) units

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Subtracting 35 both sides:

L^2-2L-35=0

Solving the quadratic equation for 'L' ;

Using factorization:

L^2+5L-7L-35=0

Taking common from the equation :

L(L+5)-7(L+5)=0\\\\(L+5)(L-7)=0\\\\L+5=0\\\\L=-5

OR

L-7=0\\\\L=7

The length cannot be negative, therefore Length(L)= 7

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Length=7units\\\\Width=5units

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4 years ago
A certain third-degree polynomial function has zeros at-5, -1, and 2. Which could NOT be a factor of the expression that defines
Kitty [74]

Answer:

I am pretty sure it is the second option

Step-by-step explanation:

Hope this helps

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2 years ago
Write the slope of the line (–12, -6) and (8, 9).<br> m=4/3<br> m=-3/4<br> m=-4/3<br> m=3/4
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Answer:

m=3/4

Step-by-step explanation:

3 0
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