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Vedmedyk [2.9K]
2 years ago
13

* 1a Average speed

Physics
1 answer:
ruslelena [56]2 years ago
4 0

Explanation:

\implies   v_{av} =  \dfrac{total \: displacement}{total \: time}

\implies   v_{av} =  \dfrac{100}{10}

\implies   v_{av} =10 \:  {ms}^{ - 1}

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A stereo speaker produces a pure \"c\" tone, with a frequency of 262 hz. what is the period of the sound wave produced by the sp
jasenka [17]

Answer:

3.82 ms

Explanation:

The period of a wave is equal to the reciprocal of the frequency:

T=\frac{1}{f}

where f is the frequency.

In this problem, f = 262 Hz, so the period if this sound wave is

T=\frac{1}{262 Hz}=3.82\cdot 10^{-3} s=3.82ms

4 0
3 years ago
A force F~ = Fx ˆı + Fy ˆ acts on a particle that
Hatshy [7]

Answer:

W = 46 J

Explanation:

We need to find the angle between the two vectors Force vector and displacement vector.

First we will find the angle α of the force vector

tan\alpha =\frac{1}{8} \\\\\\alpha =7.125 deg\\

Then we find the angle β of the displacement vector

tan\beta=\frac{2}{6} \\\\beta = 18.43 deg\\

With these two angles we can find the angle between the two vectors

∅ = α + β = 25.56 deg

The definition of work is given by the expression

W=F*d*cos (theta)

The absolute value of F will be:

F=\sqrt{8^{2}+1^{2}  } \\F= 8.06 N

The absolute value of d will be:

d=\sqrt{(6 )^{2}+(2)^{2}  } \\d= 6.32m\\

Now we have:

W=8.06*6.32*cos(25.56)\\W=46 J

4 0
3 years ago
Explain how to find the angle between two nonzero vectors. Choose the correct answer below. A. The angle between two nonzero vec
kozerog [31]

Answer:

θ = Cos⁻¹[A.B/|A||B|]

A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result

Explanation:

We can use the formula of the dot product, in order to find the angle between two non-zero vectors. The formula of dot product between two non-zero vectors is written a follows:

A.B = |A||B| Cosθ

where,

A = 1st Non-Zero Vector

B = 2nd Non-Zero Vector

|A| = Magnitude of Vector A

|B| = Magnitude of Vector B

θ = Angle between vector A and B

Therefore,

Cos θ = A.B/|A||B|

<u>θ = Cos⁻¹[A.B/|A||B|]</u>

Hence, the correct answer will be:

<u>A. The angle between two nonzero vectors can be found by first dividing the dot product of the two vectors by the product of the two vectors' magnitudes. Then taking the inverse cosine of the result</u>

3 0
2 years ago
A "570-W" electric heater is designed to operate from 120-V lines. What current does it draw? If the line voltage drops to 110 V
Viefleur [7K]

Answer:

Watts=Volt*Amps

So A=570/120=4.75amps

If voltage drops to 110V We get A=570/110=5.(18...)amps

4 0
3 years ago
Read 2 more answers
_______ are pictures of relationships.
S_A_V [24]

Answer:

Graphs

Explanation:

5 0
3 years ago
Read 2 more answers
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