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3 years ago

An explanation for planetary differentiation is_____________.

Physics

1 answer:

Luda [366]3 years ago

5 0

Answer:

C. The process through which distinct layers with characteristic chemical and/or physical properties are formed

Explanation:

I know It cause i took that test last year. Just wanna help GL.

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A ball of mass m, attached to the end of a horizontal cord, is rotated in a circle of radius r on a frictionless horizontal surf

kirza4 [7]

Answer: $v=\sqrt{\frac{FL}{m}}$

Explanation:

Given

Ball of mass m

maximum Bearable Tension in string is F

Let length of the cord be L m and moving at a speed of v m/s

Here Tension will Provide Centripetal Force

T=Centripetal Force

$F=T=\frac{mv^2}{L}$

$v=\sqrt{\frac{FL}{m}}$

8 0

3 years ago

An electron moves at a speed of 1.0 x 104 m/s in a circular path of radius 2 cm inside a solenoid. The magnetic field of the sol

iogann1982 [59]

Answer:

(a) B = 2.85 × $10^{-6}$ Tesla

(b) I = I = 0.285 A

Explanation:

a. The strength of magnetic field, B, in a solenoid is determined by;

r = $\frac{mv}{qB}$

⇒ B = $\frac{mv}{qr}$

Where: r is the radius, m is the mass of the electron, v is its velocity, q is the charge on the electron and B is the magnetic field

B = $\frac{9.11*10^{-31*1.0*10^{4} } }{1.6*10^{-19}*0.02 }$

= $\frac{9.11*10^{-27} }{3.2*10^{-21} }$

B = 2.85 × $10^{-6}$ Tesla

b. Given that; N/L = 25 turns per centimetre, then the current, I, can be determined by;

B = μ I N/L

⇒ I = B ÷ μN/L

where B is the magnetic field, μ is the permeability of free space = 4.0 × $10^{-7}$ Tm/A, N/L is the number of turns per length.

I = B ÷ μN/L

= $\frac{2.85*10^{-6} }{4*10^{-7} *25}$

I = 0.285 A

5 0

3 years ago

Two persons manage to push a motorcar of mass 1200 kg at uniform velocity along a level road, The same motorcar can be pushed by

densk [106]

Answer:

40N by each person.

Explanation:

8 0

3 years ago

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it i

andreyandreev [35.5K]

The apparent weight of a 1.1 g drop of water is 4.24084 N.

<h3>What is Apparent Weight?</h3>

According to physics, an object's perceived weight is a characteristic that describes how heavy it is. When the force of gravity acting on an object is not counterbalanced by a force of equal but opposite normality, the apparent weight of the object will differ from the actual weight of the thing.
By definition, an object's weight is equal to the strength of the gravitational force pulling on it. It follows that even a "weightless" astronaut in low Earth orbit, with an apparent weight of zero, has almost the same weight that he would have if he were standing on the ground; this is because the gravitational pull of low Earth orbit and the ground are nearly equal.

Solution:

N = Speed of rotation = 1250 rpm

D = Diameter = 45 cm

r = Radius = 22.5 cm

M = Mass of drop = 1.1 g

Angular speed of the water = $\omega = \frac{2\pi N}{60}$

$\omega = \frac{2\pi \times 1250}{60}$

$\omega = 130.89 rad/s$

Apparent weight is given by

$W _a = M\omega^{2}R$

$W_a = 1.1 \times 10^-^3\times (130.89)^2\times 0.225$

$W_a$ = 4.24084 N

Know more about Apparent weight brainly.com/question/14323035

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Question:

The spin cycle of a clothes washer extracts the water in clothing by greatly increasing the water's apparent weight so that it is efficiently squeezed through the clothes and out the holes in the drum. In a top loader's spin cycle, the 45-cm-diameter drum spins at 1250 rpm around a vertical axis. What is the apparent weight of a 1.1 g drop of water?

7 0

2 years ago

How do you solve this

Verdich [7]

Answer:

The answer is C

Explanation:

The radius is HALF of the diameter...so you would have to find a dividing "2". :)

8 0

3 years ago

Read 2 more answers