3 years ago

What is the electron configuration of helium

Chemistry

2 answers:

Troyanec [42]3 years ago

6 0

$[He]:1s^2$

mario62 [17]3 years ago

5 0

The configuration is 1s2 . Hope I answered and helped out! :)

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The rate for a reaction between reactants l, m, and n is proportional to the cube of [l] and the square of [m]. what is the rate

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Answer
rate =k[l]^3[m]^2

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3 years ago

What pressure (in atmospheres) does a gas exert when at 385 mm of Hg?

Westkost [7]

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3 years ago

Gaseous methane (CH4) will react with gaseous oxygen (O2) to produce gaseous carbon dioxide (CO) and gaseous water (H2O) . Suppo

Leto [7]

Answer:

0 g.

Explanation:

Hello,

In this case, since the reaction between methane and oxygen is:

$CH_4+2O_2\rightarrow CO_2+2H_2O$

If 0.963 g of methane react with 7.5 g of oxygen the first step is to identify the limiting reactant for which we compute the available moles of methane and the moles of methane consumed by the 7.5 g of oxygen:

$n_{CH_4}=0.963gCH_4*\frac{1molCH_4}{16gCH_4}=0.0602molCH_4\\ \\n_{CH_4}^{consumed}=7.5gO_2*\frac{1molO_2}{32gO_2}*\frac{1molCH_4}{2molO_2} =0.117molCH_4$

Thus, since oxygen theoretically consumes more methane than the available, we conclude the methane is the limiting reactant, for which it will be completely consumed, therefore, no remaining methane will be left over.

$left\ over=0g$