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Zepler [3.9K]
3 years ago
6

Which two trials could be used to measure the surface area

Chemistry
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Trials A and B

Explanation:

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Why can polar water molecules pass through a cell membrane?
TiliK225 [7]
<span> Through osmosis because the membrane is partially permeable, osmosis is the movement of water molecules from a region of lower solute concentration to a higher solute concentration.
is the answer
</span>
5 0
4 years ago
Which of the following accurately describes rill erosion?
worty [1.4K]

Answer:

C. Runoff from heavy rainfall forms narrow, shallow channels.

Explanation:

Erosion is the gradual washing away of the top layer of the soil or earth on which plant grows. There are three main types of erosion which are:

1. Sheet erosion

2. Gully erosion

3. Rill erosion

Rill erosion occurs when a soil layer is gradually being washed away by narrow stream channels called streamlets on the surface. After a heavy downpour, the streamlets facilitates the movement of water on the ground surface and in turn, earth materials are worn away.

When these streamlets becomes deeper, they form gullies. Gullies results into gully erosion.

When runoff removes soil and loose sediment in thin layers it is called sheet erosion.

4 0
3 years ago
A sample of gas has a mass of 38.8 mg. Its volume is 224 mL at a temperature of 55 °C and a pressure of 886 torr. Find the molar
Pie

Answer:

4g/mol

Explanation:

Firstly, we can get the number of moles of the gas present using the ideal gas equation.

PV = nRT

Here:

P = 886 torr

V = 224ml = 224/1000 = 0.224L

T = 55 degrees celcius= 55+ 273.15 = 328.15K

R = molar gas constant = 62.36 L⋅Torr⋅K−1⋅mol−1

n = PV/RT

n = (886 * 0.224)/(62.36 * 328.15)

n = 0.009698469964 mole

Now to get the molar mass, this is mathematically equal to the mass divided by the number of moles. We have the mass and the number of moles, remaining only the molar mass.

First, we convert the mass to g and that is 38.8/1000 = 0.0388

The molar mass is thus 0.0388/0.009698469964 = 4g/mol

3 0
4 years ago
If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?
NARA [144]

Answer:

<h3>The answer is 286.36 cm³</h3>

Explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

P_1V_1 = P_2V_2

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

V_2 =  \frac{112000 \times 259}{101300}  =  \frac{29008000}{101300}  \\  = 286.3573543...

We have the final answer as

<h3>286.36 cm³</h3>

Hope this helps you

6 0
3 years ago
The desert sand dunes seen here are are created through the processes of?
Mariana [72]
The desert sand dunes seen here are created through the process of weathering and erosion
5 0
2 years ago
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