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Zepler [3.9K]
3 years ago
6

Which two trials could be used to measure the surface area

Chemistry
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

Trials A and B

Explanation:

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What is the concentration (in M) of a 225ml potassium sulfate solution that contains 4.15g of potassium?
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The concentration of solution in M or mol/L can be calculated using the following formula:

C=\frac{n}{V} .... (1)

Here, n is number of moles and V is volume of solution in L.

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1 mol of potassium will be there in 0.5 mol of potassium sulfate.

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Number of moles can be calculated as follows:

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1 mL=10^{-3}L

Thus,

225 mL=0.225 L

Putting the values in equation (1),

C=\frac{(0.053 mol}{0.225 L}=0.236 M

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