All categories

2 years ago

Calculate the mass of water produced when 8.94 g of butane reacts with excess oxygen.

Chemistry

1 answer:

Tamiku [17]2 years ago

3 0

Yooooo this is my answer

You might be interested in

Molar mass of 34.00 g/mol molecular formula

alukav5142 [94]

Multiplying the subscripts within the empirical formula by this number gives you the molecular formula H2O2.

8 0

4 years ago

An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at

Yakvenalex [24]

Answer:

68.3g

Explanation:

1. Word equation:

mercury(II) oxide → mercury + oxygen

2. Balanced molecular equation:

2HgO → 2Hg + O₂(g)

3. Mole ratio

Write the ratio of the coefficients of the substances that are object of the problem:

$2molHgO/1molO_2$

4. Calculate the number of moles of O₂(g)

Use the equation for ideal gases:

$pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol$

5. Calculate the number of moles of HgO

$\dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO$

6. Convert to mass

mass = # moles × molar mass

molar mass of HgO: 216.591g/mol

mass = 0.315mol × 216.591g/mol = 68.3g

7 0

3 years ago

A basketball weighs approximately 1.35 kg. What is this mass in grams (g)? step by step

choli [55]

Answer:

1350 g

Explanation: just add a 0

8 0

3 years ago

According to the kinetic-molecular theory, the collision between two ideal gas particles is a result of

Svetlanka [38]

The correct answer is neither attraction nor repulsion.
Kinetic Molecular Theory explains that gas particles are in constant motion and exhibit perfectly elastic collisions. The motion of gas particles is random, meaning that there are no attractive forces on each other or on their surroundings. When two particles collide, the total kinetic energy is conserved.

4 0

3 years ago

Read 2 more answers

The molar solubility of silver bromide, AgBr in pure water is 0.0007350 mol/L. What is the

gayaneshka [121]

Answer:

0.000000540

Explanation:

Step 1: Make an ICE chart for the solution of AgBr

"S" represents the molar solubility of AgBr

AgBr(s) ⇄ Ag⁺(aq) + Br⁻(aq)

I 0 0

C +S +S

E S S

Step 2: Write the expression for the solubility product constant (Ksp)

Ksp = [Ag⁺] [Br⁻] = S × S

Ksp = S² = (0.0007350)² = 0.000000540

7 0

3 years ago