Answer:
Electrostatic Discharge during the equalization of the separated positively and negatively charged electrostatic charges in the storm clouds.
Explanation:
In nature, lightning occurs during the discharge of the large charges contained in the separated positively and negatively particles in the atmosphere in the process equalizing (neutralizing) of the charges, leading to the release of instantaneous energy in the form of heat, light and sound
During a storm, as the clouds mixes by the wind with different densities, they rub each other forming electrostatic charges. The lighter positively charged particles rise to the top clouds while the heavier negatively charged particles move to the bottom. The charges continue to add up to a point where their magnitudes is large enough such that a big spark or lightening occurs between the positive and negative charges during the process of re-equalization of the charges to revert to neutrality.
First let's find the time it takes for the first ball to land:
Acceleration is a=-g so vertical velocity is V=-gt + V1sin(30).
Position is thus
S=(-1/2)gt^2 +V1t sin(30).
Solving for t gives
t=2V1sin(30)/g
The second ball has the same position function except for the new velocity, which is given by
V2=2V1. Putting this in and solving for t2 gives
t2=4V1sin(30)/g.
It takes twice as long for the second ball to land on the ground.
The horizontal distance of ball 1 is S1 = V1t cos(30). Again we look at ball 2's distance by substituting V2=2V1 and get
S2 = 2V1t2 cos(30).
Note here I put in t2 since it will fly for that amount of time. But we already saw that
t2 = 2t1
So S2=4V1 cos(30)
That is the second ball goes 4 times further than the first one. This is because it is going twice as fast along both the horizontal and the vertical. It moves horizontally twice as fast for twice as long.
Answer:
v = 13.19 m / s
Explanation:
This problem must be solved using Newton's second law, we create a reference system where the x-axis is perpendicular to the cylinder and the Y-axis is vertical
X axis
N = m a
Centripetal acceleration is
a = v² / r
Y Axis
fr -W = 0
fr = W
The force of friction is
fr = μ N
Let's calculate
μ (m v² / r) = mg
μ v² / r = g
v² = g r / μ
v = √ (g r /μ)
v = √ (9.8 11 / 0.62)
v = 13.19 m / s
I think the answer is true
Change in velocity per time
