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andriy [413]
2 years ago
15

If a chemical reaction occurring at STP produces a change from 5 moles of gaseous reactants to 2 moles of gaseous product, what

is the overall change in volume of the system
Chemistry
1 answer:
lukranit [14]2 years ago
5 0

If the number of moles decreases from 5 moles of gaseous reactants to 2 moles of gaseous product, the overall change in volume of the system is negative.

<h3>What is volume?</h3>

Volume refers to the space occupied by an object. Gases do not have a specific volume, rather they take on the volume of the container. We must note that the volume of  given mass of gas is directly proportional to the number of moles present.

Hence, if the number of moles decreases from 5 moles of gaseous reactants to 2 moles of gaseous product, the overall change in volume of the system is negative.

Learn more about volume of a gas: brainly.com/question/22960215

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The volume of oxygen, collected over water, is 185 mL at 25 degrees Celsius and 600 torr. calculate the dry volume of the oxygen
ivolga24 [154]

Answer:

0.1593 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

  • If n and P are constant, and have two different values of V and T:

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 600 torr/760 = 0.789 atm, V₁ = 185.0 mL = 0.185 L, T₁ = 25.0°C + 273 = 298.0 K.

P₂ (at STP) = 1.0 atm, V₂ = ??? L, T₂ (at STP = 0.0°C) = 0.0°C + 273 = 273.0 K.

<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (0.789 atm)(0.185 mL)(298.0 K)/(1.0 atm)(273.0 K) = <em>0.1593 L.</em>

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3 years ago
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if I have 22.1 grams of CO2 gas at -188 degrees Celsius and 165 ml what is the pressure of the gas in kPa​
Harman [31]

Answer:

P = 2.145kPa

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R = 8.314J/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles if the gas

R = ideal gas constant

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n = number of moles

n = mass / molar mass

n = 22.1 / 44 = 0.50moles

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P = nRT/ V

P = (0.5 × 8.314 × 85.15) / 0.165

P = 2145.26Pa = 2.145kPa

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