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hichkok12 [17]
3 years ago
8

When given any reaction how do I figure out the products and then balance it?

Chemistry
1 answer:
Tju [1.3M]3 years ago
5 0
AB(aq)+C  >A +CB(aq)
hope this helps
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If a sample of gas is at 672 °C and 3.9 atm, what is the new temperature at 12.2 atm?
Snowcat [4.5K]
In order to calculate the final temperature of the gas, we may apply Charles's law, which states that the pressure and temperature of a fixed amount of gas at constant volume are directly proportional. Mathematically:
P/T = constant
(absolute temperature is used, so T = 672 + 273 = 945 K)
Thus,
3.9 / 945 = 12.2 / T
T = 2,956 K or 2,683 °C
7 0
3 years ago
What are the fields of science??
Alex Ar [27]

Answer:

Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science. These branches of natural science may be further divided into more specialized branches. But that is more writting to explain

Explanation:

7 0
3 years ago
How many grams of Ar are there in 2.25 moles of Ar?
nydimaria [60]

Answer:

89.88 g

Explanation:

Atomic Mass of Ar: 39.948

Mass = moles * AM

Replacing moles = 2.25 and AM = 39.948 you get the mass of Ar:

Mass = 2.25 * 39.948

Mass = 89.88 g

8 0
3 years ago
What’s the difference between sucrose, fructose and glucose?
Sergeeva-Olga [200]

Answer:

Explanation:

Sucrose Is Made up of Glucose and Fructose

Glucose is a simple sugar or monosaccharide.

Fructose, or “fruit sugar,” is a monosaccharide like glucose

5 0
3 years ago
Draw an electrolytic cell in which Mn2+ is reduced to Mn and Sn is oxidized to Sn2+. (Assume standard conditions).
babunello [35]

Answer:

-1.05 V

Explanation:

A detailed diagram of the setup as required in the question is shown in the image attached to this answer. The electrolytes chosen are SnCl2 for the anode half cell and MnCl2 for the cathode half cell. Tin rod and manganese rod are used as the anode and cathode materials respectively. Electrons flow from anode to cathode as indicated. The battery connected to the set up drives this non spontaneous electrolytic process.

Oxidation half equation;

Sn(s) ------> Sn^2+(aq) + 2e

Reduction half equation:

Mn^2+(aq) + 2e ----> Mn(s)

Cell voltage= E°cathode - E°anode

E°cathode= -1.19V

E°anode= -0.14 V

Cell voltage= -1.19 V - (-0.14V)

Cell voltage= -1.05 V

8 0
3 years ago
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