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RoseWind [281]
2 years ago
8

If a = 7^x , b = 7^y and a^yb^x = 49 show that xy = ​

Mathematics
1 answer:
hodyreva [135]2 years ago
4 0
I hope this helps you :)

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HELP!! PLEASE A carpenter is framing a window with wood trim where the length of the window is 9 and 1/3 feet. If the width of t
ohaa [14]
We need the perimeter of the window for framing

The window is in the shape of a rectangle with the height of 9 \frac{1}{3} feet and width of 6 \frac{3}{4}. The diagram of the shape is shown below

The perimeter of a shape is obtained by adding up the length of all the sides that form the shape.

The perimeter of the window is 9 \frac{1}{3}+9 \frac{1}{3}+6 \frac{3}{4}+6 \frac{3}{4} = 18 \frac{2}{3}+12 \frac{6}{4} 

We have two whole numbers 18 and 12 and two fractions \frac{2}{3} and \frac{6}{4}

Adding the two fractions that have different denominator 
\frac{2}{3}+ \frac{6}{4} = \frac{8}{12}+ \frac{18}{12}= \frac{26}{12}, which is an improper fraction which we can change into a mixed number 2 \frac{1}{6}

So the perimeter of the window is 
18+12+2 \frac{1}{6} =32 \frac{1}{6} 

and the length of wood needed for the frame is 32 \frac{1}{6} feet


4 0
3 years ago
Triangle CAT was rotated to create triangle C'A'T'. Describe the transformation using details and degrees.
inysia [295]

Answer:

Triangle CAT was rotated 90 degrees clockwise around the origin.

Step-by-step explanation:

The coordinate points for A and A' are (-3,3) and (3,3). The change from A to A' from quadrant 2 to 1 is a 90 degree rotation in the clockwise direction. Each of the points are equal distance from the origin (0,0) and this is the center of rotation.

6 0
3 years ago
The distribution of scores on the SAT is approximately normal with a mean of mu = 500 and a standard deviation of sigma = 100. F
ella [17]

Answer:

a. 2.28%

b. 30.85%

c. 628.16

d. 474.67

Step-by-step explanation:

For a given value x, the related z-score is computed as z = (x-500)/100.

a. The z-score related to 700 is (700-500)/100 = 2, and P(Z > 2) = 0.0228 (2.28%)

b. The z-score related to 550 is (550-500)/100 = 0.5, and P(Z > 0.5) = 0.3085 (30.85%)

c. We are looking for a value b such that P(Z > b) = 0.1, i.e., b is the 90th quantile of the standard normal distribution, so, b = 1.281552. Therefore, P((X-500)/100 > 1.281552) = 0.1, equivalently  P(X > 500 + 100(1.281552)) = 0.1 and the minimun SAT score needed to be in the highest 10% of the population is 628.1552

d. We are looking for a value c such that P(Z > c) = 0.6, i.e., c is the 40th quantile of the standard normal distribution, so, c = -0.2533471. Therefore, P((X-500)/100 > -0.2533471) = 0.6, equivalently P(X > 500 + 100(-0.2533471)), and the minimun SAT score needed to be accepted is 474.6653

4 0
3 years ago
Can someone help me solve D, a, or/and b
Margaret [11]

Answer:

slop = (175 - 125) \div (2 - 1) = 50 \\ y - 125 = 50 \times (x - 1) \\ y = 50x - 50 + 125 \\ y = 50x + 75

you can solve problems by this equation

4 0
3 years ago
Marking brainliest!!!!
Temka [501]

Answer:

D or J = 600

Step-by-step explanation:

It's hard to explain, but yeah.

Can I have brainliest?

6 0
3 years ago
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