Answer:
<h2>1.84feet</h2>
Step-by-step explanation:
Using the formula for finding range in projectile, Since range is the distance covered in the horizontal direction;
Range 
U is the velocity of the arrow
H is the maximum height reached = distance below the bullseye reached by the arrow.
R is the horizontal distance covered i.e the distance of the target from the archer.
g is the acceleration due to gravity.
Given R = 60ft, U = 250ft/s, g = 32ft/s H = ?
On substitution,

Squaring both sides we have;

The arrow will hit the target 1.84feet below the bullseye.
0.9874 the greatest non zero place is 9 but the nearest digit is 8 when you round it off to 0.9 the answer becomes 1.0
0.9874~1.0
First you distribute what’s outside the parentheses (the -4)
-4•4= -4y
-4•-2= 8
New equation: -4y+8=12
Now you solve like a normal equation
12-8 is 4
New equation: -4y=4
Now divide
Answer:-1
Answer:
x^2 + 5n = 4mx
=> x^2 - 4mx + 5n = 0
D=0 (since one root then roots are equal)
b^2-4ac = 0
(-4m)^2 - 4(1)(5n) = 0
16m^2 - 20n = 0
16m^2 = 20n
8m^2 = 10n
4m^2 = 5n
hope it helps.......
24q-8=11 (use distributive property)
24q= 11+8
24q = 20
q= 20/24
q= 0.8