The volume of the textbook calculated by the student written to 3 significant figures is 992cm³
- According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.
- To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.
- To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.
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Answer: A. A bond in which molecules share electrons
Answer:
6,41 min
Explanation:
For the reaction:
A → products
kinetics first-order reaction law is:
ln[A] = ln[A]₀ -kt
Where [A] is concentration of reactant, [A]₀ is initital concentration of reactant, k is rate constant and t is time.
If the concentration of A is 6,25% you can assume:
[A] = 6,25; [A]₀= 100. Replacing:
ln(6,25) = ln(100) -7,20×10⁻³s⁻¹t
-2,7726 = -7,20×10⁻³s⁻¹t
385s = t
In minutes:
385s×
= <em>6,41 min</em>
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I hope it helps!