Answer:
Kc = 6x10⁻⁶
Explanation:
For the reaction:
4NH₃(g) + 3O₂(g) ⇄ 2N₂(g) + 6H₂O(g)
Kc is defined as:
Kc =[N₂]² [H₂O]⁶ / [NH₃]⁴ [O₂]³
The equilibrium concentrations of the gases is -Because volume of the container is 1.00L-:
[N₂] = 2X = 1.96x10⁻³; <em>X = 9.8x10⁻⁴</em>
[H₂O] = 6X; 6ₓ9.8x10⁻⁴ = 5.88x10⁻³
[NH₃] = 0.0150M - 4X = 0.01108M
[O₂] = 0.0150M - 3X = 0.01206M
Replacing in Kc expression:
Kc =[1.96x10⁻³]² [5.88x10⁻³]⁶ / [0.01108M]⁴ [0.01206M]³
<h3>Kc = 6x10⁻⁶</h3>
Answer:
Explanation:
Compared to the process of extracting lithium from mineral deposits, the process of extracting lithium from evaporation ponds requires __less____ water, __less____ money, and ___less________ time.
Lithium extraction from salar brines are more economical to extract compared to extraction from their natural ore deposits. Salar brines occurs as liquid underground brine reservoirs. Once pumped to the surface in ponds, they are left to evaporate and the lithium is concentrated from them. Extraction from brines in ponds do not require water that much, less cost and if the evaporation rate is fast, a lot of time can be saved.
Extraction from mineral deposits require a lot of energy and time to achieve.
Answer:
0.46M NaS₂O₃ (Assuming KIO₃ solution with a concentration of 1.0M)
Explanation:
Based on the reaction:
6 Na₂S₂O₃ + KIO₃ + 5 KI + 3 H₂SO₄ → 3 Na₂S₄O₆ + 3 H₂O + 3 K₂SO₄ + 6 NaI
<em>6 moles of Na₂S₂O₃ react per mole of KIO₃</em>
Assuming the molarity of the KIO₃ solution is 0,1M:
Moles of KIO₃: = 5.0x10⁻³L ₓ (0.1 mol / L) = <em>5.0x10⁻⁴ moles</em>
As 6 moles of thiosulfate reacted per mole of iodate:
5.0x10⁻⁴ moles KIO₃ ₓ (6 moles Na₂S₂O₃ / 1 mole KIO₃) =
<em>3.0x10⁻³ moles of Na₂S₂O₃. </em>In 6.5mL (6.5x10⁻³L):
3.0x10⁻³moles Na₂S₂O₃ / 6.5x10⁻³ L = 0.46M NaS₂O₃
Since the half life of the radioactive isotope is 4,000 years, after 4,000 years the amount of the isotope would decrease by half. (Hence the name, half life.) So, after 4,000 years, there would be half of the isotope left in the fossil.
Answer:
Neutralization is when the pH (power of hydrogen ions) of a solution is at 7 (considered neutral in the pH scale). This means it's neither acidic nor basic and is neutral. In order to neutralize an acidic solution, you pour in the same amount of a strong base. And in order to neutralize a basic solution, you pour in the same amount of a strong base.
A neutralization reaction will give you salt and water. A common neutralization reaction could be:
HCl (strong acid) + NaOH (strong base) ----> NaCl (Salt) + H2O (water)
