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2 years ago

Can anyone explain to me the octet rule in detail with examples my teacher didn't do the greatest job of making us understand.

1 answer:

iogann1982 [59]2 years ago

4 0

In chemistry, the octet rule explains how atoms of different elements combine to form molecules. In a chemical formula, the octet rule strongly governs the number of atoms for each element in a molecule; for example, calcium fluoride is CaF2 because two fluorine atoms and one calcium satisfy the rule. Hope this helps

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What climate zone is asia?

dolphi86 [110]

Answer:

The Tundra Climate

Explanation:

:) hope this helps

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2 years ago

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In the laboratory a student determines the specific heat of a metal. She heats 19.6 grams of zinc to 98.37°C and then drops it i

fgiga [73]

Answer:

The specific heat of zinc is 0.375 J/g°C

Explanation:

Step 1: Data given

Mass of zinc = 19.6 grams

Mass of water = 82.9 grams

Initial temperature of zinc = 98.37 °C

Initial temperature of water = 24.16 °C

Final temperature of water (and zinc) = 25.70 °C

Specific heat of water = 4.184 J/g°C

Step 2: Calculate Specific heat of zinc

Heat lost by zinc = heat won by water

Q=m*c*ΔT

Qzinc = -Qwater

m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)

⇒ with mass of zinc = 19.6 grams

⇒ with C(zinc) = TO BE DETERMINED

⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C

⇒ with mass of water = 82.9 grams

⇒ with C(water) = 4.184 J/g°C

⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54

Qzinc = -Qwater

19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C

-1424.332*C(zinc) = -534.155

C(zinc) = 0.375 J/g°C

The specific heat of zinc is 0.375 J/g°C

7 0

3 years ago

The factor that affects how easily an electron can be removed from an atom is the

Shkiper50 [21]

Temperature of the environment, surrounding atoms and size of atom are all factors which affect removal of electron. Increase in temperature increases the probability of removal of electron. But size of the atom plays very important role in removal of electrons. In case of large sized atom, the nuclear attraction of nucleus on valence electrons decreases which eases the removal of electrons. Hope this helps.

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3 years ago

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If wave A has a frequency of 4.60 x 10^14 s-1, what is the wavelength in nanometers (show your work)?

victus00 [196]

Answer:

652.174nm

Explanation:

We need to know that the speed of light never changes. It has a value of 3 × 10^8 m/s.

Given only the frequency, we can find the wavelength by dividing the value of the speed of light by the value of the frequency.

That equals = (3 × 10^8) ÷ ( 4.6 × 10^14) = 0.000000652174 m = 652.174 ÷ 10^-9m = 652.174nm

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