Answer:
H2O
H2O
Explanation:
because the are only two hydrogen that can react to Oxygen
<u>Answer:</u> The electronic configuration of the elements are written below.
<u>Explanation:</u>
Electronic configuration is defined as the representation of electrons around the nucleus of an atom.
Number of electrons in an atom is determined by the atomic number of that atom.
For the given options:
- <u>Option a:</u> Carbon (C)
Carbon is the 6th element of the periodic table. The number of electrons in carbon atom are 6.
The electronic configuration of carbon is 
- <u>Option b:</u> Phosphorus (P)
Phosphorus is the 15th element of the periodic table. The number of electrons in phosphorus atom are 15.
The electronic configuration of phosphorus is 
- <u>Option c:</u> Vanadium (V)
Vanadium is the 23rd element of the periodic table. The number of electrons in vanadium atom are 23.
The electronic configuration of vanadium is 
- <u>Option d:</u> Antimony (Sb)
Antimony is the 51st element of the periodic table. The number of electrons in antimony atom are 51.
The electronic configuration of antimony is 
- <u>Option e:</u> Samarium (Sm)
Samarium is the 62nd element of the periodic table. The number of electrons in samarium atom are 62.
The electronic configuration of samarium is 
Hence, the electronic configuration of the elements are written above.
<span>b. square root of 3 over 3 is the answer to your question!!! I hope I helped!!!!!!!!!! XoXo -Marcey<3! :D
</span>
Because when you take the sand out it doesn't stay the same shape
Answer:
A) CH3CH2SH
Explanation:
Dispersion forces are weak attractions found between non-polar and polar molecules. The attractions here can be attributed to the fact that a non-polar molecule sometimes become polar because the constant motion of its electrons may lead to an uneven charge distribution at an instant. If this happens, the molecule has a temporary dipole. This dipole can induce the neighbouring molecules to be distorted and form dipoles as well. The attractions between these dipoles constitute the Dispersion Forces.
Therefore; the greater the molar mass of a compound or molecule, the higher the Dispersion Force. This implies that the compound or molecule with the highest molar mass have the largest dispersion forces.
Now; for option (A)
CH3CH2SH
The molar mass is :
= (12 + (1 × 3 ) +12 + (1 ×2) + 32+1)
= (12 + 3+ 12 + 2 + 32 + 1)
= 62 g/mol
For option (B)
CH3NH2
The molar mass is:
= (12 + (1 × 3 ) +14 + (1 × 2)
= (12 + 3 + 14 + 2)
= 31 g/mol
For option (C)
CH4
The molar mass is :
= 12 + (1 × 4)
= 12 + 4
= 16 g/mol
For option (D)
CH3CH3
The molar mass is :
= 12 + ( 1 × 3 ) + 12 + ( 1 × 3)
= 12 + 3 + 12 + 3
= 30 g/mol
Thus ; option (A) has the highest molar mass, as such the largest dispersion force is A) CH3CH2SH