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iragen [17]
3 years ago
11

Explain how the valence electrons are related to the element's period.

Chemistry
1 answer:
AlekseyPX3 years ago
5 0

Answer:

The number of valence electrons in an atom is reflected by its position in the periodic table of the elements (see the periodic table in the Figure below). Across each row, or period, of the periodic table, the number of valence electrons in groups 1–2 and 13–18 increases by one from one element to the next

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Name three pure elements and three pure compounds​
VARVARA [1.3K]

Answer:

Pure elements:

Hydrogen(H)

Nitrogen(N)

Magnesium (Mg)

Pure Compounds:

Oxygen gas(O2)  

Water (H2O)  

Ammonia (NH3)

Explanation:

Hope it helps.Please mark me brainliest.^-^

5 0
3 years ago
Choose the number of significant figures indicated 0.06
Alex17521 [72]

Answer:

2

Explanation:

8 0
3 years ago
What is a controlled factor in an experiment?
Romashka-Z-Leto [24]
Sorry this will probably be pretty long.

So think of the "control" as being something you yourself add to increase or decrease the effects in an experiment.
I'll give you an example so it is not as confusing.
Say you have decided to make an experiment on plants. Which plant can grow the fastest on which type of liquid? What is being added to this experiment? The liquid! Or all of the liquids you used. Like if you used Coke, Lime Gatorade, Orange Gatorade, and Water. Each drink will EFFECT each plant differently.
Hope I was of any hope?
3 0
3 years ago
What main factor determines the path a star will take during its life cycle
OLEGan [10]
The Nassau Din beat the the star has.
It may turn into a black hole if it has a high enough mass.
5 0
4 years ago
Calculate the molarity of each of the following
Alenkasestr [34]

Answer:

a. 1.21M

b. 0.119M

c. 0.00496M

Explanation:

Molarity, M, is an unit of concentration defined as the ratio between moles of solute and liters of solution:

a. 4.35 mol LiCl / 3.60L = 1.21M

b. 29.43gC6H12O6 * (1mol / 180.16g) = 0.1634moles / 1.37L = 0.119M

<em>Molar mass C6H12O6: 180.16g/mol</em>

c. 34.5mg NaCl = 0.0345g * (1mol / 58.44g) = 5.9x10⁻⁴moles / 0.1191L = 0.00496M

8 0
3 years ago
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