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Archy [21]
2 years ago
7

Jamison walks to a friends house. He walks 1000 meters north, then realizes he walked to far so he turns around and walks 200 me

ters south. The entire walk takes him 12 minutes. What is his average velocity in meters per second.
Physics
1 answer:
olasank [31]2 years ago
4 0

We will find that his average velocity is 1.11 m/s north-wise.

<h3>How to get the average velocity?</h3>

We define average velocity as the quotient between the displacement and the time it takes to make that displacement.

We know that he starts at the point 0m, where this measures distance in the north direction.

Then he moves 1000 meters north, so the new position is 1000m.

Then he moves 200 meters south, so the new position is:

1000m - 200m = 800m.

The displacement is equal to the difference between the final position (800m) and the initial position (0m).

D = 800m - 0m = 800m.

And we know that it takes 12 minutes to walk that distance. Because we want the average velocity in meters per second, we write:

12 minutes = 12*(60 seconds) = 720s

Then the average velocity is just:

AV = (800m)/(720s) = 1.11 m/s

And the direction of this average velocity is north-wise.

If you want to learn more about average velocity, you can read:

brainly.com/question/4931057

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A 150kg person stands on a compression spring with spring constant 10, 000 N/m and norminal.Length of 0.50.What is the togal len
Eva8 [605]

Answer:

Total length of spring 0.647 m

Explanation:

We have given mass of the person m = 150 kg

Acceleration due to gravity g=9.8m/sec^2

Spring constant k = 10000 N/m

Nominal length of spring = 0.50

According to hook's law

mg=kx

150\times 9.8=10000\times x

x = 0.147 m

So total length of spring = 0.50+0.147 = 0.647 m

4 0
3 years ago
Radiation in the ultraviolet region of the electromagnetic spectrum is quite energetic. It is this radiation that causes dyes to
N76 [4]

The  energy of photon in kJ/mol is 329kJ/mol.

Wavelength of radiation is 370nm. The frequency of given wavelength is

            ν = c / λ

            ν = 3×10^8 / 370×10^-9

            ν = 8.11 × 10^14 s^-1

      Now the energy of photon is:

             E = hν

             E = 6.63×10^-34  J.s/photon × 8.11×10^14s^-1

             E = 5.41× 10^-19  J/photon

         To find in mole

              E = 5.41× 10^-19 × 6.022×10^23

               E = 3.29 ×10^ 5 J/mol

   So, the energy of mole of photon is equal to 329 kJ/mol.

        Learn more about radiation here:

                brainly.com/question/18650102

                     #SPJ4  

5 0
2 years ago
The device used to measure a masses of a body is kilogram . true or false​
olga nikolaevna [1]

Answer: false

Explanation:

While kilograms are the unit used to measure body mass, the device used is a scale.

Hope it helps :)

6 0
3 years ago
A projectile is launched upward at an angle of 70⁰ from the horizontal and strikes the ground a certain distance down range. For
OLga [1]

Answer:20°

Explanation:

Recall

Range R of a projectile is given by U^2sin2A/g

We're U = velocity,A= angle of projection and g is acceleration due to gravity

From the question the range R are the same

Hence R1=R2

U1^2sin2A/g=U2^2sin2B/g

But U1=U2 and g=g

Hence sin2A=sin 2B

Sin 2*70= sin2*B

0.6427=sin2B

B=sin inverse(0.6427)=40/2=20°

7 0
3 years ago
The capacitor is now disconnected from the battery, and the plates of the capacitor are then slowly pulled apart until the separ
alexdok [17]

Answer:

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

Explanation:

The energy stored in a capacitor is given by (1/2) (CV²)

Energy in the capacitor initially

U = CV²/2

V = voltage across the plates of the capacitor

C = capacitance of the capacitor

But the capacitance of a capacitor depends on the geometry of the capacitor is given by

C = ϵA/d

ϵ = Absolute permissivity of the dielectric material

A = Cross sectional Area of the capacitor

d = separation between the capacitor

So,

U = CV²/2

Substituting for C

U = ϵAV²/2d

Now, for U₁, the new distance between plates, d₁ = 3d

U₁ = ϵAV²/2d₁

U₁ = ϵAV²/(2(3d))

U₁ = (ϵAV²)/6d

This means that the new energy of the capacitor is (1/3) of the initial energy before the increased separation.

3 0
3 years ago
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