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3 years ago

14

A 150kg person stands on a compression spring with spring constant 10, 000 N/m and norminal.Length of 0.50.What is the togal len

gth of the loaded spring?

1 answer:

Eva8 [605]3 years ago

4 0

Answer:

Total length of spring 0.647 m

Explanation:

We have given mass of the person m = 150 kg

Acceleration due to gravity $g=9.8m/sec^2$

Spring constant k = 10000 N/m

Nominal length of spring = 0.50

According to hook's law

$mg=kx$

$150\times 9.8=10000\times x$

x = 0.147 m

So total length of spring = 0.50+0.147 = 0.647 m

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A brick lands 10.1 m from the base of a building. If it was given an initial velocity of 8.6 m/s [61º above the horizontal], how

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<h2>Answer: 10.52m</h2><h2 />

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$X=V_{ox}.t$ (5)

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$y$ is the height of the building (<u>in this case it has a negative sign because of the reference system we chose)</u>

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