Question

A force of 200 N stretches a spring 30 cm. What is the spring constant of the spring? How far would this spring stretch with a force of 100 N applied to it?

Answer 1

Hooke's Law

F = k. Δx

Δx = 30 cm = 0.3 m

200 = k . 0.3

$\tt k =\dfrac{200}{0.3}= 666.6$

the spring stretch for 100 N:

$\tt \Delta x=\dfrac{100}{666.6}=0.15=15\:cm$