Ask question

Ask question

All categories

2 years ago

15

A force of 200 N stretches a spring 30 cm. What is the spring constant of the spring? How far would this spring stretch with a f

orce of 100 N applied to it?

1 answer:

bija089 [108]2 years ago

4 0

Hooke's Law

F = k. Δx

Δx = 30 cm = 0.3 m

200 = k . 0.3

$\tt k =\dfrac{200}{0.3}= 666.6$

the spring stretch for 100 N:

$\tt \Delta x=\dfrac{100}{666.6}=0.15=15\:cm$

You might be interested in

The coordinates of a bird flying in the xy-plane are given by x(t)=αt and y(t)=3.0m−βt2, where α=2.4m/s and β=1.2m/s2.part a:Cal

8090 [49]

Α $=2.4 \frac{m}{s}$

β $=1.2 \frac{m}{s^2}$

$x(t)=at$

$y(t)=3-$ β $t^2$

$Vx(t)=$ α

$Vy(t)=-2$ β $t$

$vectorV=[$ α $;-2$ β $t]$

$ax(t)=0$

$ay(t)=-2$ β $t$

$vector a [0;-2$ β $t]$

3 0

3 years ago

A force of 10 n acts on a mass of 5 kg producing an acceleration of 1.5 m/s2 what is the magnitude of the force of friction acti

prisoha [69]

The friction is 2.5N. The Net force is 10 N - 2.5 N .= 7.5 N.
acceleration = 7.5 / 5 = 1.5 m/s^2

8 0

2 years ago

A tennis ball was thrown straight up with initial velocity of 22.5 m/s. How high does the ball rise

kiruha [24]

Answer:

$h_m=25.8\ m$

Explanation:

<u>Vertical Launch Upwards</u>

In a vertical launch upwards, an object is launched vertically up without taking into consideration friction with the air.

If vo is the initial speed and g is the acceleration of gravity, the maximum height reached by the object is given by:

$\displaystyle h_m=\frac{v_o^2}{2g}$

The tennis ball was thrown straight up with a speed of v0=22.5 m/s. The acceleration of gravity is g=9.81\ m/s^2, thus:

$\displaystyle h_m=\frac{22.5^2}{2\cdot 9.81}$

$\mathbf{h_m=25.8\ m}$

6 0

2 years ago

1, 2, & 3.........................

oksian1 [2.3K]

Answer:

1 is correct

2 is -150

4 0

2 years ago

In loading a lorry, a man lifts boxes each of weight 100N through a height of 1.5m.

liq [111]

Answer:

The amount of work done in order to lift the box is $150\ Joule$

Explanation:

Given the weight of each box is $100N$

And the man lifts boxes at a height of $1.5m$

We need to find the amount of work done.

The amount of work done is the product of applied force $F$ that causes the displacement $d$ .

In our problem force is $100N$ and displacement is $1.5m$ .

Now, work done

$=force\times displacement\\=100\times1.5\\=150\ Joule$

So, the amount of work done in order to lift the box is $150\ Joule$

5 0

2 years ago