The equation has one zero, and the system has three solutions ( 1 real and 2 complex solutions).
<h3>
Solution of the polynomial equation</h3>
The solution of the polynomial equation is determined as follows;
3x³ + x = 2x² + 1
3x³ - 2x² + x - 1 = 0

Thus, we can conclude that the equation has one zero (real solution), and the system has three solutions ( 1 real and 2 complex solutions).
Learn more about polynomial equations here: brainly.com/question/2833285
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Answer:
See below
Explanation:
Vertical component of initial velocity = 200 sin 35° = 114.72 m/s
then use position formula a = 9.81 m/s^2
0 = 300 + 114.72 t - 1/2 (9.81)(t^2)
use quadratic formula with a = - 4.905 b = 114.72 c = 300
to find t = <u>25.76 seconds </u>
<u />
To find the range
( horizontal distance the projectile lands from launch point)
Horizontal component of initial velocity 200 cos 35 = 163.83 m/s
( it flies horizontally at this speed for <u>25.76 seconds <==found above</u>)
163.83 m/s * 25.76 s = <u>4220.3 meters</u>
Answer:
a) 
b) 
c) 
d) 
Explanation:
a) The initial vertical velocity is given by:

Where:
θ: 25°
v: is the magnitude of the speed = 23 m/s

b) The initial horizontal velocity can be calculated as follows:

c) The flight time can be calculated using the following equation:

Where:
x: is the total distance = 42 m

d) The maximum height is given by:
Where:
: is the final vertical velocity =0 (at the maximum heigth)
g: is the gravity = 9.81 m/s²
I hope it helps you!
So i believe is exercise:)