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lisabon 2012 [21]
3 years ago
5

What is gravity at north pole, South pole and at different point on the equatorial regions. Give reasoning for your answers why

do you think it is different or same. Can you imagine same concept for the electric charge, yes or No
Physics
1 answer:
Radda [10]3 years ago
4 0

Answer:

The gravity at Equator is 9.780 m/s2 and the gravity at poles is 9.832 m/s2. The gravity at poles are bigger than at equator, principally because the Earth is not totally round. The gravity is inversely proportional to the square of the radius, that is the reason for the difference of gravity (The radius at Poles are smaller than at Equator).

If Earths would have a net charge Q. The Electric field of Earth would be inversely proportional to the square of the radius of Earth (Electric field definition for a charge), the same case as for gravity. So there would be a difference between the electric field at poles and equator, too.

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A researcher collected data on 100 random homes in Wake County. She then created the following histogram of when each home was b
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Answer:

The correct answer is "The median year built is greater than the mean year built., The median year built is between 1980 and 2000."

Explanation:

Wake country is located in the north Carolina, it is the most fastest growing country among the united nations. The town of Cary and also city of Raleigh is the 8th and the 15th fastest growing cities. Hence, the city was growing along with infrastructures as well as with the population. For proper shelter more number of the homes were built. The literacy rates were also good. A quite good number of schools and colleges are there in the city. With better medical facilities.

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All of the following elements produce magnetic fields except
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The answer should be copper. hope this helps :D
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If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
stich3 [128]
I would think that you would have to do 42/2=21Hz, but I'm not sure...
5 0
3 years ago
With a mass of 109 kg, Baby Bird is the smallest monoplane ever
OLga [1]

Total resultant velocity=5.11-3.27=1.84m/s

  • m_1=61.4kg
  • m_2=109kg
  • v_1=1.84m/s
  • v_2=?

\\ \sf\longmapsto ∆P=P

\\ \sf\longmapsto m_1v_1=m_2v_2

\\ \sf\longmapsto v_2=\dfrac{m_1v_1}{m_2}

\\ \sf\longmapsto v_2=\dfrac{61.4(1.84)}{109}

\\ \sf\longmapsto v_2=112.976/109

\\ \sf\longmapsto v_2\approx 1.3m/s

4 0
3 years ago
A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel
trasher [3.6K]

Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

1\ mile=1609.34\ m

1\ h=3600\ seconds

18.03\times \frac{3600}{1609.34}=40.33\ mph

Speed of the boat by when it will hit the dock is 40.33 mph

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m

The distance at which the boat will have to start decelerating is 312.5 m

5 0
3 years ago
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