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In-s [12.5K]
2 years ago
5

A water droplet falling in the atmosphere is spherical. Assume that as the droplet passes through a cloud, it acquires mass at a

rate proportional to kA where k is a constant (k>0) and A is its cross-sectional area. Consider a droplet of initial radius r0 that enters a cloud with a velocity v0. Assume no resistive force and show:
a. that the radius increases linearly with the time
b. that if r0 is negligibly small then the speed increases linearly with the time within the cloud.
Physics
1 answer:
ArbitrLikvidat [17]2 years ago
4 0

Answer:

it b

Explanation:

bc A water droplet falling in the atmosphere is spherical

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Speed uses distance and velocity uses displacement in its calculation.

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Which of the following results when a crest and trough meet?
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An object weighs 60.0 kg on the surface of the earth. How much does it weigh 4R from the surface? (5R from the center)
Alecsey [184]
"60 kg" is not a weight.  It's a mass, and it's always the same
no matter where the object goes.

The weight of the object is   

                                 (mass) x (gravity in the place where the object is) .

On the surface of the Earth,

                   Weight = (60 kg) x (9.8 m/s²)

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Now, the force of gravity varies as the inverse of the square of the distance from the center of the Earth.
On the surface, the distance from the center of the Earth is 1R.
So if you move out to  5R  from the center, the gravity out there is

                    (1R/5R)²  =  (1/5)²  =  1/25  =  0.04 of its value on the surface.

The object's weight would also be 0.04 of its weight on the surface.

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Again, the object's mass is still 60 kg out there.
___________________________________________

If you have a textbook, or handout material, or a lesson DVD,
or a teacher, or an on-line unit, that says the object "weighs"
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6 0
3 years ago
What does x repressent on a motion map?​
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6 0
3 years ago
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Six identical resistors are connected in series with a battery. The number of joules per second supplied by the battery is then
Nataly_w [17]

Answer:

The option (b) is correct.

Explanation:

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It is given in the problem that a seventh resistor is added (in series).

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P=\frac{V^{2}}{R}

Here, R is the resistance.

From the above expression, it can be concluded that the power, the number of joules per second supplied by the battery is inversely proportional to the resistance. The equivalent resistance increases if the seventh resistance is connected with a battery.

If a seventh resistor is added (in series) the number of joules per second supplied by the battery decreases.

Therefore, the option (b) is correct.

5 0
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