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Answer:
16.12
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The difference between velocity and relative velocity is that velocity is measured with respect to a reference point which is relative to a different point. While relative velocity is measured in a frame where an object is either at rest or moving with respect to the absolute frame.
To solve this problem we will apply the concepts related to destructive interference from double-slit experiments. For this purpose we will define the path difference as,

Here,
= Wavelength
= Angle when occurs the interference point of destructive interference
Our values are given as,


Using the previous expression we have,





Therefore the distance between the two openings is 