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Scilla [17]
3 years ago
7

What are the products of the neutralization reaction of KOH with HCL

Chemistry
1 answer:
ioda3 years ago
3 0

Answer:

The products are KCl (potassium chloride) and H20 (water)

Explanation:

Hydrochloric acid (strong acid) reacts completely with potassium hydroxide (strong base) in a neutralization reaction (also called acid-base), giving as products: water and a salt (potassium chloride).

HCl + KOH---> KCl + H20

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Tetrachloromethane, CCl4, is classified as a
Soloha48 [4]
Correct Answer: <span>compound because the atoms of the elements are combined in a fixed proportion.

Reason:
A </span><span> chemical </span>compound is a chemical substance composed of element (of same or different type) that are bonded in a fixed proportion. Depending upon the type of element, bond can be ionic or covalent. In present case, <span>tetrachloromethane i.e. CCl4 has one 'C' atom that is covalently bonded to four 'Cl' atoms. </span>
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True or False<br> Helium belongs to Noble Metals
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Answer:

This answer is "True"

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1. We have new knowledge of how charge can be transferred from one object to another
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5 0
1 year ago
0.023 M solution of perchloric acid
kogti [31]
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)
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