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Scilla [17]
3 years ago
7

What are the products of the neutralization reaction of KOH with HCL

Chemistry
1 answer:
ioda3 years ago
3 0

Answer:

The products are KCl (potassium chloride) and H20 (water)

Explanation:

Hydrochloric acid (strong acid) reacts completely with potassium hydroxide (strong base) in a neutralization reaction (also called acid-base), giving as products: water and a salt (potassium chloride).

HCl + KOH---> KCl + H20

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Answer:

D. As white light passes through a prism , it bends and separates into different colors

Explanation:

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3 years ago
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2 years ago
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3 years ago
0.58 mol of Mg contains how many atoms? please show work
Jet001 [13]

The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms

<h3>Avogadro's hypothesis </h3>

1 mole of Mg = 6.02×10²³ atoms

<h3>How to determine the atoms in 0.58 mole of Mg </h3>

1 mole of Mg = 6.02×10²³ atoms

Therefore,

0.58 mole of Mg = 0.58 × 6.02×10²³

0.58 mole of Mg = 3.49×10²³ atoms

Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg

Learn more about Avogadro's number:

brainly.com/question/26141731

#SPJ1

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