Answer:
B
B
A
C
Explanation:
3
B. Vanillin as a phenoxide ion (conjugate base)
4
B. Protonation of acetic anhydride
5
A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride
6
C. 1 mmol of vanillin and 10.6 mmol acetic anhydride
Answer:
4.96 mol/dm³
Explanation:
From the question,
Mass of NaCl that dissolved in 0.5L of water = 500-346.8 = 153.2 g.
Therefore, 145.2(1/0.5)g of NaCl will dissolve in 1 L of water
mass of NaCl that will dissolve in 1 L of water = 290.4 g/dm³
Molar mass of NaCl = 58.5 g/mol.
Solubility is the amount of substance in mol that will dissolve in 1 L or 1 dm³ Solution.
solubility in (mol/dm³) = solubility in (g/dm³)/molar mass.
solubility in (mol/dm³) = 290.4/58.5
solubility in (mol/dm³) = 4.96 mol/dm³
Super saturated solution is formed.
<u>Explanation:</u>
Solubility is the property of any substance's capacity, that is the solute of the substance is dissolved in the given solvent to form the solution. We have three different types of solution, unsaturated, saturated and supersaturated solution.
- Unsaturated solution is a solution with lesser amount of solute than its solubility at equilibrium.
- Saturated solution is a solution with the maximum solute dissolved in the solvent.
- Super saturated solution is a solution with more solute than it is required.
The solubility of KI at 30°C is 153 g / 100 ml. Here 180 g of KI in 100 ml of water at 30°C is given, which has more solute than required, so it is super saturated solution.
The answer for this problem is 305.2 because you múltipley and thats how you get the answer by mulyiplying
