Answer:
About 547 grams.
Explanation:
We want to determine the mass of copper (II) bicarbonate produced when a reaction produces 2.95 moles of copper (II) bicarbonate.
To do so, we can use the initial value and convert it to grams using the molar mass.
Find the molar mass of copper (II) bicarbonate by summing the molar mass of each individual atom:
Dimensional Analysis:
In conclusion, about 547 grams of copper (II) bicarbonate is produced.
The answer is B. Because think about it, it’s not a scientific fact that brown dogs are better pets, and the best color for your room isn’t it because the answer would be an opinion of someone not a fact. I hope this might help you.
Are there choices? Because if there are that would help A LOT, but if there are no choices I can give some examples of physical properties, though there are MILLIONS, here are a few :) .
Physical property examples are: color, smell, freezing point, boiling point, melting point, attraction or repulsion to magnets and viscosity and density. If these are not options, please let me know :)
Have a great day, let me know if I can help with anything else, have a great day, and, if you have time, mark brainiest, I would really appreciate it, thanks! :D
Answer:
3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.
Explanation:
Iron(III) chloride is also known as Iron trichloride and it has the molar mass value of 162.2 g/mol and density of 2.9 g/cm³.
<em>The balanced equation for the chemical reaction between solid calcium and iron (III) chloride is given below as: </em>
<em />
3Ca₍s₎ + 2FeCl₃ -------------------------------------------------------------> 3CaCl₂ + 2Fe₍s₎.
This kind of chemical reaction is known as <em>single displacement reaction or single replacement reaction. </em>
Answer:
Mass of ring = 32 g
Volume of ring = 4 mL
Density of ring = 8 g/mL
Explanation:
From the question given above, the following data were obtained:
Mass of ring = 32 g
Volume of water = 64 mL
Volume of water + ring = 68 mL
Density of ring =?
Next, we shall determine the volume of the ring. This can be obtained as follow:
Volume of water = 64 mL
Volume of water + ring = 68 mL
Volume of ring =?
Volume of ring= (Volume of water + ring) – (Volume of water)
Volume of ring = 68 – 64
Volume of ring = 4 mL
Finally, we shall determine the density of the ring. This can be obtained as follow:
Mass of ring = 32 g
Volume of ring = 4 mL
Density of ring =?
Density = mass / volume
Density of ring = 32 / 4
Density of ring = 8 g/mL
