1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
inn [45]
2 years ago
15

Helpppppppppppppppppppppppppppp

Chemistry
1 answer:
arlik [135]2 years ago
8 0

Answer:

can you send link

Explanation:

You might be interested in
6. What causes the phases of the moon?
lawyer [7]

Answer:

The rotation of the Earth.

6 0
2 years ago
How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?
slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between  reaction between calcium chloride and aluminum oxide is given as,

3CaCl_{2} (aq)+Al_{2} O_{3} (s) → 3CaO_{2} (s)+2Al Cl_{3} (aq)

The molar ratio of above reaction is  3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with  5. 99 moles of  aluminum oxide  = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

learn more about calcium chloride

brainly.com/question/15296925

#SPJ4

6 0
2 years ago
A closed, frictionless piston-cylinder contains a gas mixture with the following composition on a mass basis: 40% carbon dioxide
Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

n_{CO_2}=0.8kg*0.4*\frac{1kmolCO_2}{44kgCO_2}= 0.00727kmolCO_2\\\\n_{O_2}=0.8kg*0.25*\frac{1kmolO_2}{32kgO_2}=0.00625kmolO_2\\ \\n_{Ne}=0.8kg*0.35*\frac{1kmolNe}{20.2kgNe}=0.0139kmolNe

Next, the total moles:

n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol

After that, since the process is isobaric, we can compute the work as:

W=P(V_2-V_1)

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3

Thereby, the magnitude and direction of work turn out:

W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0
3 years ago
what is the change in the velocity of the biker below as he travels from point b to point c ? ..... What is his acceleration fro
Furkat [3]

The change in the velocity = 4 m/s

Acceleration = 4 m/s²

<h3>Further explanation</h3>

Given

vo = initial velocity = 4 m/s

vf = final velocity = 8 m/s

t = 1 s

Required

The change in the velocity

Acceleration

Solution

the change in velocity =

\tt vf-vo=8-4=4~m/s

Acceleration = ratio of a change in velocity and the time

\tt a=\dfrac{\Delta v}{t}= \dfrac{vf-vo}{t}

Input the value :

\tt a=\dfrac{4~m/s}{1~s}=4~m/s^2

7 0
2 years ago
How many kilojoules are released when 8.2 g of water condenses at 100 °c and cools to 15 °c?
MrRa [10]

Answer:- 2.92 kJ of heat is released.

Solution:- We have water at 100 degree C and it's going to be cool to 15 degree C.

So, change in temperature, \Delta T = 15 - 100 = -85 degree C

mass of water, m = 8.2 g

specific heat of water, c = 4.184\frac{J}{^0C.g}

The equation used for solving this type of problems is:

q=mc\Delta T

Let's plug in the values in the equation and solve it for q which is the heat energy:

q = (8.2)(4.184)(-85)

q = -2916.248 J

They want answer in kJ. So, let's convert J to kJ and for this we divide by 1000.

q=-2916.248J(\frac{1kJ}{1000J})

q = -2.92 kJ

Negative sign indicates the heat is released. So, in the above process of coiling of water, 2.92 kJ of heat is released.

3 0
3 years ago
Other questions:
  • Compound X has the same molecular formula as butane but has a different boiling point and melting point. What can be concluded a
    6·1 answer
  • If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the
    14·1 answer
  • A physical property may be investigated by
    15·1 answer
  • Gaseous butane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 10. g of butane is m
    15·1 answer
  • Lake Eola is a sinkhole lake. What reasoning best describes how it formed?
    5·2 answers
  • Photosynthesis is an example of a
    11·1 answer
  • Comment se nomme le processus qui permet à une cellule- mere de donner deux cellules-filles
    8·1 answer
  • What are the chemical properties of acids​
    6·1 answer
  • Which term describes the repeated arrangement of the same molecule?
    8·1 answer
  • A
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!