Answer:
a. the work done by the gravitational force on Block A is <u>less than</u> the work done by the gravitational force on Block B.
b. the speed of Block A is <u>equal to</u> the speed of Block B.
c. the momentum of Block A is <u>less than</u> the momentum of Block B.
Explanation:
a. The work done by the gravitational force is equal to:
w = m*g*h
where m is mass, g is the standard gravitational acceleration and h is height. Given that both blocks are released from rest at the same height, then, the bigger the mass, the bigger the work done.
b. With ramps frictionless, the final speed of the blocs is:
v = √(2*g*h)
which is independent of the mass of the blocks.
c. The momentum is calculated as follows:
momentum = m*v
Given that both bocks has the same speed, then, the bigger the mass, the bigger the momentum.
Answer:
a) —0.5 j m/s
b) 4.5 i + 2.25 j m
Explanation:
<u>Givens:</u>
v_0 =3.00 i m/s
a= (-3 i — 1.400 j ) m/s^2
The maximum x coordinate is reached when dx/dt = 0 or v_x = 0 ,thus :
<em>v_x = v_0 + at = 0 </em>
(3.00 i m/s) + (-3 i m/s^2)t=0
t = (3 m/s)/-3 i m/s^2
t = -1 s
Therefore the particle reaches the maximum x-coordinate at time t = 1 s.
Part a The velocity-of course- is all in the y-direction,therefore:
v_y =v_0+ at
We have that v_0 = 0 in the y-direction.
v_y = (-0.5 j m/s^2)(1 s)
= —0.5 j m/s
Part b: While the position of the particle at t = 1 s is given by:
r=r_0+v_0*t+1/2*a*t^2
Where r_0 = 0 since the particle started from the origin.
Its position at t = 1 s is then given by :
r =(3.00 i m/s)(1 s)+1/2(-3 i — 1.400 j )(1 s)^2
=4.5 i + 2.25 j m
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Answer:
Dry Arid, Coastal, Mountains
Explanation:
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