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marshall27 [118]
3 years ago
11

Use the net below. 288cm 312cm 336cm 368cm

Mathematics
1 answer:
vichka [17]3 years ago
8 0
Add all shapes area together to know the figures complete area
triangles area 1 & 2 : 6×8 /2 -> 48/2 = 24
rectangle 1 : 6×12 -> 72
rectangle 2 : 8×12 -> 96
rectangle 3 : 10×12 -> 120
24+72+96+120
96+96+120
192+120
312cm
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What is a base of 3 with an exponent of-3??<br>​
DaniilM [7]

Answer:

The answer is 1/27

Step-by-step explanation:

3^-3 can be written as 1/3^3 and 3^3 = 3x3x3= 27

Therefore, the answer is 1/27.

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Mr. Lopez has 238 silver coins in his coin collection. The actual weight of the real silver in each coin is 0.85 ounce. How many
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Answer:

202.3 ounces of real silver

Step-by-step explanation:

Another example would be like pizza. If there are 6 slices of pizza in each box, then 2 boxes of pizza would have 6 + 6 slices = 12 slices. It is 6 slices each * 2 boxes = 12 slices total. The same applies to the coin situation, for every additional coin, multiply 0.85 by the number of coins to get the total weight of real silver.

If there are 238 silver coins, then you have 238 0.85 ounces of real silver. Multiplying 238 by 0.85 to simplify gives you 202.3 ounces of real silver.

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Rafael graphed a line that contains the points (4, –6) and (–2, 6). What is the slope of the line that he graphed?
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In triangle ABC we have angle C = 3 times angle A, a=27 and c=48 What is b? Note: a is the side length opposite A etc. please he
Dima020 [189]

Answer:

  35

Step-by-step explanation:

The law of sines tells us ...

  sin(C)/c = sin(A)/a

  a·sin(3A) = c·sin(A)

Using the identity sin(3x) = 3cos(x)·sin(x) -sin(x)^3 and sin(x)^2 +cos(x)^2 = 1, we can simplify this to ...

  sin(A)(4cos(A)^2 -1) = (c/a)sin(A)

  4cos(A)^2 = c/a +1 = (48+27)/27 = 75/27 = 25/9

  cos(A)^2 = 25/36

  cos(A) = 5/6

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Now, the angle B will be the difference between 180° and the sum of the other two angles:

  B = 180° -A -3A = 180° -4A

Using appropriate trig identities, we can write ...

  sin(B) = 4cos(A)^3sin(A) -4sin(A)^3cos(A)

  = 4sin(A)cos(A)(cos(A)^2 -sin(A)^2)

  = 4sin(A)cos(A)(2cos(A)^2 -1)

Filling in our value for cos(A), this becomes ...

  sin(B) = 4sin(A)(5/6)(2(5/6)^2-1) = sin(A)(35/27)

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The law of sines tells us ...

  b/sin(B) = a/sin(A)

  b = a·sin(B)/sin(A) = 27(35/27)sin(A)/sin(A) = 35

The length of side b is 35 units.

6 0
3 years ago
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