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2 years ago

So, your task this week is a maths problem;

1 answer:

5 0

Answer: Sam and Morgan met up at 18:00. Sam left Exeter at 10:00, and was on the road for 7 hours. I know this because 175 / 25 = 7. 10:00 + 7:00 = 17:00 meaning Sam got there at 17:00. Morgan on the other hand left at 13:00 and had an average speed of 35 mph. 175/35=5. 13:00 + 5:00 = 18:00. By 18:00 both Sam and Morgan had arrived in London thus 18:00 us your answer.

Step-by-step explanation:

You might be interested in

A sequence of Bernoulli trials consists of choosing components at random from a batch of components. A selected component is eit

Drupady [299]

Answer:

a) 0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

Step-by-step explanation:

A sequence of Bernoulli trials composes the binomial distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

The probability that a selected component is non-defective is 0.8

This means that $p = 0.8$

a) Three non-defective components in a batch of seven components.

This is P(X = 3) when n = 7. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 3) = C_{7,3}.(0.8)^{3}.(0.2)^{4} = 0.0287$

0.0287 = 2.87% probability that three non-defective components in a batch of seven components.

b) 8 non-defective components are drawn before the first defective component is chosen.

Now the order is important, so the we just multiply the probabilities.

8 non-defective, each with probability 0.8, and then a defective, with probability 0.2. So

$p = (0.8)^8*0.2 = 0.0336$

0.0336 = 3.36% probability that 8 non-defective components are drawn before the first defective component is chosen.

4 0

3 years ago

The graph of a polynomial S(x) = (2x - 3)(x – 4)(x+3) has x-intercepts at 3.x values.

dezoksy [38]

Answer:

Step-by-step explanation:

x-intercepts exist where y is equal to 0. Where y is equal to 0 is where the graph goes through the x-axis. Our x-intercepts are (2x-3), (x + 3), and (x-4). Again, since x-intercepts exist where y = 0, then by the Zero Product Property, 2x - 3 = 0, x - 4 = 0, and x + 3 = 0. In the first x-intercept:

2x - 3 = 0 and

2x = 3 so

x = 3/2

In the second:

x - 4 = 0 so

x = 4

In the third:

x + 3 = 0 so

x = -3

So the x-intercepts in the correct order are x = 3/2, 4, -3

6 0

3 years ago