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anygoal [31]
2 years ago
9

So, your task this week is a maths problem;

Mathematics
1 answer:
BaLLatris [955]2 years ago
5 0

Answer: Sam and Morgan met up at 18:00. Sam left Exeter at 10:00, and was on the road for 7 hours. I know this because 175 / 25 = 7. 10:00 + 7:00 = 17:00 meaning Sam got there at 17:00. Morgan on the other hand left at 13:00 and had an average speed of 35 mph. 175/35=5. 13:00 + 5:00 = 18:00. By 18:00 both Sam and Morgan had arrived in London thus 18:00 us your answer.

Step-by-step explanation:

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PLEASE HELP TIMED
rusak2 [61]

A - drawing a red 8

B - drawing an 8


P(A|B)=\dfrac{P(A\cap B)}{P(B)}\\\\ |\Omega|=52\\ |A\cap B|=2\\ |B|=4\\\\ P(A \cap B)=\dfrac{2}{52}=\dfrac{1}{26}\\ P(B)=\dfrac{4}{52}=\dfrac{1}{13}\\\\ P(A|B)=\dfrac{\dfrac{1}{26}}{\dfrac{1}{13}}=\dfrac{1}{26}\cdot13=\dfrac{1}{2}

5 0
3 years ago
The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).
Alchen [17]

Answer:

(3,3)

Step-by-step explanation:

Given

Vertices: (0,0)\ (1,0)\ (0,1)

Scale\ Factor = 3

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

New\ Vertex = Scale\ Factor * Old\ Vertex

For (0,0):

New\ Vertex = 3 * (0,0)

New\ Vertex = (3 * 0,3 * 0)

New\ Vertex = (0,0)

For (1,0):

New\ Vertex = 3 * (1,0)

New\ Vertex =  (3 * 1,3 * 0)

New\ Vertex =  (3,0)

For (0,1):

New\ Vertex =  3 * (0,1)

New\ Vertex =  (3 * 0,3 * 1)

New\ Vertex =  (0,3)

<em>Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle</em>

<em></em>

5 0
3 years ago
4√6 •√3 how do I show work for this because the answer is 2√12​
Yuliya22 [10]

Answer:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

Step-by-step explanation:

We want to simplify the radical expression:

4 \sqrt{6}  \times  \sqrt{3}

We write √6 as √(2*3).

This implies that:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2 \times 3}   \times  \sqrt{3}

We now split the radical for √(2*3) to get:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  \sqrt{3}  \times  \sqrt{3}

We obtain a perfect square at the far right.

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times  (\sqrt{3} )^{2}

This simplifies to

4 \sqrt{6}  \times  \sqrt{3}  = 4 \sqrt{2}  \times 3

This gives us:

4 \sqrt{6}  \times  \sqrt{3}  = 4 \times 3 \sqrt{2}

and finally, we have:

4 \sqrt{6}  \times  \sqrt{3}  = 12 \sqrt{2}

5 0
3 years ago
What is the factored form of 8x2 + 12x? 4(4x2 + 8x) 4x(2x + 3) 8x(x + 4) 8x(x2 + 4)
earnstyle [38]
So I'm guessing that the x2 is your way of saying 2 is the exponent right? In that case the equation would be 8x^2 + 12x
Well you would have to pull out the gcf which in this case will be 4x after pulling out the gcf you should get 4x(2x + 3)
8 0
4 years ago
Read 2 more answers
From the top of a 100-ft building a man
romanna [79]

Answer:

219m

Step-by-step explanation:

Since the man observes the car with angle 15 before observing in 33 degrees.

For the first observation

The angle observation gives an angle if 33 degrees with the horizontal.

It gives a triangle which I'll attach to the que,

from the first triangle

Tan 33 = 100/y

Y= 100/ tan 33

Y = 153.99m.

This is the distance from the building to the distance where it was secondly observed( 33).

To find x

tan 15 = 100/(153.99+x)

153.99 + x = 100/ tan 15

153.99 + x = 373.21

The distance between the two observed angles

X= 219m.

5 0
3 years ago
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