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Novosadov [1.4K]
2 years ago
15

A runner wants to run 11.7 km. Her running pace is 8.0 mi/hr. How many minutes must she run?

Chemistry
1 answer:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

8 mi = 12.875 km

12.875 /60 m

= 0.21458 km / min

11.7 / 0.21458 = 54.52 min

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3-chloropropylamine what is?
marta [7]

Answer:

a chemical compound

6 0
2 years ago
For an alloy that consists of 91.0 g copper, 111 g zinc, and 7.51 g lead, what are the concentrations (a) of Cu (in at%), (b) of
viktelen [127]

Answer:

\% Cu=45.2\%\\\\\% Zn=53.6\%\\\\\% Pb=1.2\%

Explanation:

Hello!

In this case, given the masses of copper, zinc and lead, it is possible to compute the moles via their atomic masses first:

n_{Cu}=\frac{91.0gCu}{63.55g/mol}=1.432mol\\\\ n_{Zn}=\frac{111gZn}{65.41g/mol}=1.697mol\\\\n_{Pb}=\frac{7.51gPb}{207.2g/mol}=0.0362mol\\

Now, we compute the atomic percentages as shown below:

\% Cu=\frac{1.432}{1.432+1.697+0.0362}*100\% =45.2\%\\\\\% Zn=\frac{1.697}{1.432+1.697+0.0362}*100\%=53.6\%\\\\\% Pb=\frac{0.0362}{1.432+1.697+0.0362}*100\%=1.2\%

Best regards!

4 0
3 years ago
If the actual yield of a reaction is 37.6 g while the theoretical yield is 112.8 g what is the percent yield
Zigmanuir [339]
<h2>Hello!</h2>

The answer is:

The percent yield of the reaction is 32.45%

<h2>Why?</h2>

To calculate the percent yield, we have to consider the theoretical yield and the actual yield. The theoretical yield as its name says is the yield expected, however, many times the difference between the theoretical yield and the actual yield is notorious.

We are given that:

ActualYield=37.6g\\TheoreticalYield=112.8g

Now, to calculate the percent yield, we need to divide the actual yield by the theoretical and multiply it by 100.

So, calculating we have:

PercentYield=\frac{ActualYield}{TheoreticalYield}*100\\\\PercentYield=\frac{37.6g}{112.8g}*100=0.3245*100=32.45(percent)

Hence, we have that the percent yield of the reaction is 32.45%.

Have a nice day!

8 0
4 years ago
Read 2 more answers
If I make a salt solution that has 1 grams of salt and 9 grams of water the percentage of salt in my solution is _____.
Soloha48 [4]

Answer:

10%

Explanation:

4 0
3 years ago
If you are administering an insulin dose of 90.0 mg from a bottle at a concentration of 10.0 mg/mL,
Fiesta28 [93]

Answer:

9 mL.

Explanation:

Dosage of insulin is 90 mg

The concentration of insulin is 10 mg/mL

We need to find how many milliliters of the solution do you need to give the patient. It can be calculated as follows :

x=\dfrac{90\ \text{mg}}{10\dfrac{\text{mg}}{\text{mL}}}\\\\x=\dfrac{9}{1}\ \text{mL}

So, 9 mL of the solution is to be given to the patient.

4 0
3 years ago
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