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irinina [24]
3 years ago
8

In order to design an experiment you need a ____ about the scientific question you are trying to answer

Physics
2 answers:
s2008m [1.1K]3 years ago
6 0

C Hypothesis. It is the correct answer.

Nutka1998 [239]3 years ago
4 0
I think C:Hypothesis
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Explain why it took so long for psychology to be recognized and what things helped it to get recognized.
Juli2301 [7.4K]
It took so long because at the time there was no way for people to study the behavior formally. im not sure what helped it get recognized but i know wihelm wundt helped get it recongnized. 

sorry i couldnt be much help
4 0
3 years ago
The end diastolic volume of a heart is 140 mL Assume that it is a sphere. At end diastole, the intraventricular pressure is 7mmI
Vera_Pavlovna [14]

Answer:

Explanation:

We know that, V = 140 mL = 0.00014 m3

Assume that it is a sphere. so, we have

V = (4/3) \pir3

r3 = (0.00014 m3) (3) / (4) (3.14)

r = \sqrt[3]{}\sqrt[3]{}3\sqrt{}3.34 x 10-5 m3

r = 1.93 x 10-7 m

(a) The wall tension at end diastole will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end diastole = 7 mmHg = 933.2 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (933.2 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

T = 8.18 x 10-3 N

(b) The wall tension at the end of isovolumetric contraction will be given as :

using a formula, we have

T = P r / 2 H

where, P = intraventricular pressure at end of isovolumetric contraction = 80 mmHg = 10665.7 Pa

H = wall thickness at this time = 0.011 m

then, we get

T = (10665.7 Pa) (1.93 x 10-7 m) / 2 (0.011 m)

T = 9.35 x 10-2 N

(d) The wall stress from A and B which will be given as :

we know that, \sigma = T / w

For part A, we have

\sigmaA = (8.18 x 10-3 N) / (0.011 m)

\sigmaA = 0.743 N/m

For part B, we have

\sigmaB = (9.35 x 10-2 N) / (0.011 m)

\sigmaB = 8.5 N/m

4 0
2 years ago
In freefall, heavier objects fall with a greater acceleration than lighter objects.
Rom4ik [11]

Answer:

That is not true all objects fall at the same speed excepts things like feathers or paper.

6 0
3 years ago
Read 2 more answers
A car with a mass of 1,500 kg is accelerating at a rate of
AURORKA [14]

Answer:

The net force acting on the car is

3

×

10

3

Newtons.

Hope this helps you

Explanation:

Force is defined as the product of the mass of the body and its aaceleration,

⇒

F

=

m

a

Substituting the above given values we get,

F

=

(

1500

k

g

)

(

2.0

m

/

s

2

)

=

3000

N

=

3

×

10

3

N

.

4 0
2 years ago
what will be the speed of a solid sphere of mass 2.0 kilograms and radius 15.0 centimeters when it reaches the bottom of a incli
Yuki888 [10]

Explanation:

Below is an attachment containing the solution.

4 0
3 years ago
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