Answer:
The flux through the surface of the cube is ![2.314\ Nm^{2}/C](https://tex.z-dn.net/?f=2.314%5C%20Nm%5E%7B2%7D%2FC)
Solution:
As per the question:
Edge of the cube, a = 8.0 cm = ![8.0\times 10^{- 2}\ m](https://tex.z-dn.net/?f=8.0%5Ctimes%2010%5E%7B-%202%7D%5C%20m)
Volume Charge density, ![\rho_{v} = 40 nC/m^{3} = 40\times {- 9}\ C/m^{3}](https://tex.z-dn.net/?f=%5Crho_%7Bv%7D%20%3D%2040%20nC%2Fm%5E%7B3%7D%20%3D%2040%5Ctimes%20%7B-%209%7D%5C%20C%2Fm%5E%7B3%7D)
Now,
To calculate the electric flux:
(1)
where
= electric flux
= permittivity of free space
Volume Charge density for the given case is given by the formula:
(2)
Volume of cube, ![V = a^{3}](https://tex.z-dn.net/?f=V%20%3D%20a%5E%7B3%7D)
Thus
![V = (8.0\times 10^{- 2})^{3} = 5.12\times 10^{- 4}\ m^{3}](https://tex.z-dn.net/?f=V%20%3D%20%288.0%5Ctimes%2010%5E%7B-%202%7D%29%5E%7B3%7D%20%3D%205.12%5Ctimes%2010%5E%7B-%204%7D%5C%20m%5E%7B3%7D)
Thus from eqn (2), the total charge is given by:
![q = \rho_{v}V = 40\times {- 9}\times 5.12\times 10^{- 4}](https://tex.z-dn.net/?f=q%20%3D%20%5Crho_%7Bv%7DV%20%3D%2040%5Ctimes%20%7B-%209%7D%5Ctimes%205.12%5Ctimes%2010%5E%7B-%204%7D)
![q = 2.048\times 10^{-11}\ F = 20.48\ pF](https://tex.z-dn.net/?f=q%20%3D%202.048%5Ctimes%2010%5E%7B-11%7D%5C%20F%20%3D%2020.48%5C%20pF)
Now, substitute the value of 'q' in eqn (1):
![\phi = \frac{2.048\times 10^{-11}}{8.85\times 10^{- 12}} = 2.314\ Nm^{2}/C](https://tex.z-dn.net/?f=%5Cphi%20%3D%20%5Cfrac%7B2.048%5Ctimes%2010%5E%7B-11%7D%7D%7B8.85%5Ctimes%2010%5E%7B-%2012%7D%7D%20%3D%202.314%5C%20Nm%5E%7B2%7D%2FC)
Helium only has 2 electrons. So the answer is C. 2
Answer:
2.16×10⁻⁶ N
Explanation:
Applying,
F = kqq'/r² (coulomb's Law)....................... Equation 1
Where F = electrostatic force, k = coulomb's constant, q = charge on the styrofoam, q' = charge on the grain of salt, r = distance between the charges.
From the question,
Given: q = 0.002 mC = 2.0×10⁻⁶ C, q' = 0.03 nC = 3.0×10⁻¹¹ C, r = 0.5 m
Constant: k = 8.99×10⁹ Nm²/C²
Substitute these values into equation 1
F = (2.0×10⁻⁶)(3.0×10⁻¹¹)(8.99×10⁹)/0.5²
F = 2.16×10⁻⁶ N
Answer:
Explanation:
capacitance of capacitor
= ε₀ A / d , A is area of plate , d is plate separation
= (8.85 x10⁻¹² x 1.7² x 10⁻⁴) /( .35 x 10⁻³ )
= 73 x 10⁻¹³ F
Charge = 4.5 x 10⁻⁷
voltage between the plates,
Δ V = charge / capacitance
= 4.5 x 10⁻⁷ / 73 x 10⁻¹³
= .0616 x 10⁶
= 616 x 10² V
To make the vottage double , we will reduce capacitance to half .
To reduce capacitance half we will increase plate distance to double.
new plate distance
= 1.7 x 2
= 3.4 cm
Answer:
Acceleration = 2.8 m/s²
Explanation:
Given the following data;
Mass = 1500 kg
Net force = 4200 Newton
To find the truck's acceleration;
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
Substituting into the formula, we have;
Acceleration = 2.8 m/s²