Ruby is out with her friends. Misfortune occurs and
1 answer:
The work done is
Explanation:
The work done by a force on an object is given by:
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
In this problem, we have
F = 1080 N is the force applied on the car
d = 218 m is the displacement of the car
And assuming the force is applied parallel to the motion of the car, , and so the work done is
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Answer:
2.83 m/s
Explanation:
Given:
Mass of the cart (m) = 20.0 kg
Initial velocity of the cart (u) = 0 m/s
Final velocity (v) = ? m/s
Displacement of the cart (S) = 8.0 m
Horizontal force acting on the cart (F) = 10.0 N
Surface is frictionless. So, only horizontal force is the force acting on the cart.
Now, as per work-energy theorem, the work done by the net force acting on a body is equal to the change in the kinetic energy of the body.
Here, the work done by the horizontal force is given as:
The change in kinetic energy is given as:
Now, from work-energy theorem:
Therefore, the speed of the cart when it has been pushed 8.0 m is 2.83 m/s.