Answer:
c. 9 det A
Step-by-step explanation:
Given the following data;
Since A is a square matrix of order 2, we know that n = 2
K = 3
For any scalar k;
∣kA∣ = k^{n} ∣A∣
<em>Substituting into the equation;</em>
∣-3A∣ = -3²∣A∣
Simplifying, we have;
∣-3A∣ = 9∣A∣
= 9 detA
<em>Therefore, det (-3A) = 9 detA</em>
Answer:
700
Step-by-step explanation:
539 rounded to 500
221 rounded to 200
500 plus 200 is 700
for f(x) = -2(x-4)2+2 - set equation to y = -2(x-4)2+2, solve x-4=0, x = 4
axis of symmetry is x = 4
for g(x) = 5x2-10x+7, set equation to y = 5x2-10x+7, solve the square: 5x2 becomes 5(x-1)2 solve x-1 = 0, x = 1
axis of symmetry is x=1
for H(x) what x value would be the centerline so that the graph symmetry is the same on both sides? looking at the graph the top of the arc is on -2
so axis of symmetry is x = -2
to do this all you have to do is make the denominator 1 and the numerator should be 1.566666667
Answer:
The answer is below
Step-by-step explanation:
The complete question is given in the image attached below
m∠1 + m∠2 = 180° (sum of angles on a straight line)
m∠1 + 98 = 180
m∠1 = 180 - 98
m∠1 = 82°
m∠2 + m∠3 + m∠7 = 180° (sum of angles in a triangle)
98 + 23 + m∠7 = 180
m∠7 + 121 = 180
m∠7 = 180 - 121
m∠7 = 59°
m∠4 = m∠7 (alternate angles)
m∠4 = 59°
m∠6 + m∠7 + m∠8 = 180° (sum of angles on a straight line)
m∠6 + 59 + 70 = 180
m∠6 + 129 = 180
m∠6 = 180 - 129
m∠6 = 51°
m∠4 + m∠8 + m∠9 = 180° (sum of angles in a triangle)
59 + 70 + m∠9 = 180
m∠9 + 129 = 180
m∠9 = 180 - 129
m∠9 = 51°
m∠4 + m∠5 = 180° (sum of angles on a straight line)
m∠5 + 59 = 180
m∠5 = 180 - 59
m∠5 = 121°
m∠10 + m∠9 = 180° (sum of angles on a straight line)
m∠10 + 51 = 180
m∠10 = 180 - 51
m∠10 = 129°