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2 years ago

What are properties of a base

Chemistry

2 answers:

Ilya [14]2 years ago

5 0

Maybe this we’ll help?

omeli [17]2 years ago

4 0

Answer:

base taste bitter
base feel so spy slippery to touch
base turn wet red litmus paper blue

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What are the coefficients that belong in the blanks to balance the following chemical equation?

brilliants [131]

Answer:

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

Explanation:

silver(I) iodide + sodium sulfide ⟶ silver(I) sulfide + sodium iodide

1. Convert the word equation to a chemical equation:

AgI + Na₂S ⟶ Ag₂S + NaI

2. Put a 1 in front of the most complicated-looking formula (Na₂S?):

AgI + 1Na₂S ⟶ Ag₂S + NaI

3. Balance Na:

We have fixed 2 Na on the left. We need 2 Na on the right. Put a 2 in front of NaI.

AgI + 1Na₂S ⟶ Ag₂S +2NaI

4. Balance S:

We have fixed 1 S on the left. We need 1 O on the right. Put a 1 in front of Ag₂S.

AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

5. Balance Ag:

We have fixed 2Ag on the right. We need 2 Ag on the left. Put a 2 in front of AgI.

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

Every formula now has a coefficient. The equation should be balanced.

6. Check that atoms balance:

Atom On the left On the right

Ag 2 2

I 2 2

Na 2 2

S 1 1

The balanced equation is

2AgI + 1Na₂S ⟶ 1Ag₂S +2NaI

4 0

4 years ago

Does changing the number of neutrons change the identity of the element you have built ?

worty [1.4K]

Answer:

If you change the number of neutrons somehow, nothing will happen because it carry's no charge at all.

Explanation:

4 0

4 years ago

What kind of material makes ice cream

aivan3 [116]

Is it milk and nitrogen? Hope this helps!

7 0

3 years ago

Read 2 more answers

How many grams of P4O10 (292.88 g/mol) form when phelpsphorous (P4, 125.52 g/mol) reacts with 16.2 L of O2 (33.472 g/mol) ) at s

nevsk [136]

Answer:

40.5 g of P₄O₁₀ are produced

Explanation:

We state the reaction:

P₄ + 5O₂ → P₄O₁₀

We do not have data from P₄ so we assume, it's the excess reactant.

We need to determine mass of oxygen and we only have volumne so we need to apply density.

Density = mass / volume, so Mass = density . volume

Denstiy of oxygen at STP is: 1.429 g/L

1.429 g/L . 16.2L = 23.15 g

We determine the moles: 23.15 g . 1mol / 33.472g = 0.692 moles

5 moles of O₂ can produce 1 mol of P₄O₁₀

Our 0.692 moles may produce (0.692 . 1)/ 5 = 0.138 moles

We determine the mass of product:

0.138 mol . 292.88 g/mol = 40.5 g

3 0

3 years ago

If you only have 36.5 grams of Potassium Carbonate (K2CO3 molar mass = 138.2 g/mole). How many liters of a 0.52 M solution can y

kirza4 [7]

Answer:

0.508 L of solution.

Explanation:

Always a safe bet to convert to moles:

$n= {m \over MM}\\$

Where n is moles, m is mass, and MM is molar mass.

Now remember the equation for concentration (molarity):

$C={n \over V}$

Where C is the concentration, n is moles, and V is volume.

To make this easy, combine the two equations (note n appears in both, so you can do a substitution) and solve for V as the question asks:

$C={m \over MM \times V}\\0.52={36.5 \over 138.2 \times V}\\V={36.5 \over 138.2 \times 0.52}\\V=0.508$

Therefore we can make 0.508 L of solution.

8 0

3 years ago