The number of molecules of hydrogen will be required to produce 1.60 mol of water are 9.6×10²³.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the relative amount of moles of reactants and products present in the given chemical reaction.
Given chemical reaction is:
2H₂ + O₂ → 2H₂O
From the stoichiometry of the reaction,
2 moles of hydrogen = produces 2 mole of water
1.6 moles of hydrogen = produces 1.6 mole of water
As we know that in 1 mole of any substance 6.022×10²³ entities of that substance are present.
In 1.6 mole of H₂ gas = (1.6)(6.022×10²³) = 9.6×10²³ molecules of hydrogens are present.
Hence 9.6×10²³ molecules of hydrogens are present.
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Answer:
0.295 mol/L
Explanation:
Given data:
Volume of solution = 3.25 L
Mass of BaBr₂ = 285 g
Molarity of solution = ?
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of solute:
Number of moles = mass/ molar mass
Molar mass of BaBr₂ = 297.1 g/mol
Number of moles = 285 g/ 297.1 g/mol
Number of moles= 0.959 mol
Molarity:
M = 0.959 mol / 3.25 L
M = 0.295 mol/L
Answer:
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Explanation:
