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castortr0y [4]
3 years ago
15

How to assign oxidation and reduction numbers

Chemistry
1 answer:
Ann [662]3 years ago
4 0

Answer:Rule 1: The oxidation number of an element in its free (uncombined) state is zero — for example, Al(s) or Zn(s). This is also true for elements found in nature as diatomic (two-atom) elements

Explanation:

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ROY G BIV arranges the colors of the rainbow *
Elanso [62]

Answer:

Wavelengths..

Explanation:

The colors we see always go from red, which is least refracted, through orange, yellow, green, blue, indigo and violet -- Roy G Biv. The blue, indigo and violet wavelengths are refracted the most as sunlight passes through raindrops.

8 0
3 years ago
Which of the following is a clue that something is pseudoscience?
adelina 88 [10]
D i think if not here’s this a collection of beliefs or practices mistakenly regarded as being based on scientific method
7 0
3 years ago
What is the name of a solution whose concentration of solute is equal to the maximum concentration that is predicted from the so
faltersainse [42]

<u>Answer:</u> The correct answer is saturated solution.

<u>Explanation:</u>

For the given options:

Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.

Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.

Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent.  The concentration of the solute particles that can be dissolved in a solution is maximum.

Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.

From the above information, we conclude that the given solution is saturated solution.

7 0
3 years ago
Read 2 more answers
Write balanced, net ionic equations for the following precipitation, acidn base, or gasn forming reactions. Include states of ma
dybincka [34]

Answer:

Explanation:

a ) 2FeCl₃ + 3Li₂S  = Fe₂S₃ ( s )  + 6 LiCl

2Fe⁺³ + 6Li ⁻ + 6Cl⁻ + 3S⁻² = 6Li + 6Cl⁻ + Fe₂S₃ ( s )

b  )

3CH₃COONa +( NH₄)₃PO₄ = 3CH₃COONH₄ + Na₃PO₄

3CH₃COO + 3Na⁺ +  3NH₄⁻  +  PO₄⁺³  = 3CH₃COO⁻ +3NH₄⁺ + Na₃PO₄

c )

HClO₄  + KOH = kClO₄ + H₂O

H ⁺ + ClO₄⁻ +  K⁺ + OH⁻  =  k⁺  ClO₄⁻  + H₂O

d )

NH₄OH + HNO₃ = NH₄NO₃  + H₂O

NH₄⁺ + OH⁻ + H⁺ + NO₃⁻ = NH₄⁺ + NO₃⁻ +  H₂O

e )

HNO₂ + KOH = KNO₂ + H₂O

H⁺ + NO₂⁻ + K⁺ + OH⁻ = K⁺ + NO₂⁻ + H₂O

f ) HIO₃ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

H⁺ + IO₃⁻ + CaCO₃ ( s ) = Ca( IO₃ )₂ + H₂CO₃

g )

c ) is strong acid and strong base

d ) is weak base and strong acid

e ) weak acid and strong base

f ) Strong acid and basic salt

5 0
3 years ago
From the amount of NaOH added at the 1st equivalence point, calculate the original molarity of the acid. Carry out the same calc
gizmo_the_mogwai [7]

Answer:

Molarity of acid, Ca = Cb*Vb*A/Va*B

Explanation:

Using H2SO4 as acid, the reaction is as follow:

2NaOH  +  H2SO4 ⇒ Na2SO4  +  2H2O

Volume of acid = Va; Volume of base = Vb, Molar concentration of  acid = Ca; Molar concentration of base = Cb; Molarity of acid = A and Molarity of base = B

Ca*Va/Cb*Vb =A/B

∴ Ca = Cb*Vb*A/Va*B

4 0
3 years ago
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