HELP ME OUT PLS!!!
1 answer:
You might be interested in
Answer:
170 g
Explanation:
Moles of Oxygen gas :
Given, Mass of Oxygen = 80.0 g
Molar mass of Oxygen gas= 31.998 g/mol
The formula for the calculation of moles is shown below:
Thus,
The reaction between Al and O₂ is shown below as:
4Al + 3O₂ ⇒ 2Al₂O₃
From the reaction,
3 moles of O₂ on reaction forms 2 moles of Al₂O₃
1 mole of O₂ on reaction forms 2/3 moles of Al₂O₃
2.5 moles of O₂ on reaction forms (2/3)*2.5 moles of Al₂O₃
Moles of Al₂O₃ = 1.6667 moles
Molar mass of Al₂O₃ = 102 g/mol
Mass = Moles * Molar mass = 1.6667 * 102 g = 170 g
Answer: 0.3794 moles of Iodine gas are produced.
Explanation:
Volume of iodine gas produced at STP =8.5 L
At STP, the 1 mol of gas occupies volume = 22.4 L
So, 8.5 L of volume will be occupied by:
0.3794 moles of Iodine gas are produced.