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Irina-Kira [14]
2 years ago
14

PLEASE HELP. I NEED THIS FOR TOMMOROW. WILL GIVE BRAINLIEST ​

Physics
1 answer:
Fantom [35]2 years ago
3 0

Ansthethethethethe

the is the is

Explanation:

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Prepare a stock available at home following the procedure you learned in this lesson. Have a picture of the finished product and
Bingel [31]

Answer:

NO, 1. is stocks

2. is also stocks

bouquit GARNI IS NUMBER 3

NUMBER 4 IS ACID PRODUCTS

number 5 is brown stock

Explanation:

stocks are bones

6 0
3 years ago
an astronaut on an eva has wandered dangerously far away from the shuttle. she has also exhausted all the fuel in her jet pack.
V125BC [204]

The conservation of the momentum allows to find the result of how the astronaut can return to the spacecraft is:

  • Throwing the thruster away from the ship.

The momentum is defined as the product of the mass and the velocity of the body, for isolated systems the momentum  is conserved. If we define the system as consisting of the astronaut and the evo propellant, this system is isolated and the internal forces become zero. Let's find the moment in two moments.

Initial instant. Astronaut and thrust together.

        p₀ = 0

Final moment. The astronaut now the thruster in the opposite direction of the ship.

       m_f = m v + M v '

where m is propellant mass and M the astronaut mass.

As the moment is preserved.

       0 = m v + M v ’

      v ’= - \frac{m}{M} \ v  

We can see that the astronaut's speed is in the opposite direction to the propeller, that is, in the direction of the ship.

The magnitude of the velocity is given by the relationship between the masses.

In conclusion, using the conservation of the momentun we can find the result of how the astronaut can return to the ship is:

  • Throwing the thruster away from the ship.

Learn more here:  brainly.com/question/14798485

5 0
2 years ago
What is the relationship between velocity and kinetic energy?
faltersainse [42]

Answer:

when an object has more velocity, it tends to have less potential energy and more kinetic energy.

Explanation:

kinetic energy is the energy of movment and velocity helps to describe movement

4 0
3 years ago
A physicist drives through a stop light. When he is pulled over, he tells the police officer that the Doppler shift made the red
makkiz [27]

Answer:

Explanation:

\lambda = Observed wavelength = 550 nm

\lambda' = Actual wavelength = 635 nm

c = Speed of light = 3\times 10^8\ \text{m/s}

v = Velocity of the physicist

Doppler shift is given by

f=\sqrt{\dfrac{c+v}{c-v}}f'\\\Rightarrow \dfrac{c}{\lambda}=\sqrt{\dfrac{c+v}{c-v}}\dfrac{c}{\lambda'}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}=\dfrac{c+v}{c-v}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}=\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}(1-\dfrac{v}{c})=1+\dfrac{v}{c}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}(1-\dfrac{v}{c})=1+\dfrac{v}{c}\\\Rightarrow \dfrac{\lambda'^2}{\lambda^2}-1=\dfrac{v}{c}(1+\dfrac{\lambda'^2}{\lambda^2})\\\Rightarrow v=\dfrac{c(\dfrac{\lambda'^2}{\lambda^2}-1)}{1+\dfrac{\lambda'^2}{\lambda^2}}

\Rightarrow v=\dfrac{3\times 10^8\times (\dfrac{635^2}{550^2}-1)}{1+\dfrac{635^2}{550^2}}\\\Rightarrow v=42817669.77\ \text{m/s}

The physicist was traveling at a velocity of 42817669.77\ \text{m/s}.

4 0
3 years ago
Titania, the largest moon of the planet Uranus, has 1/8 the radius of the earth and 1/1700 the mass of the earth.What is the acc
garri49 [273]

Answer:

(a). The acceleration due to gravity at the surface of Titania is 0.37 m/s².

(b). The average density of Titania is 1656.47 kg/m³

Explanation:

Given that,

Radius of Titania R_{t}= \dfrac{1}{8}R_{e}

Mass of Titania M_{t}= \dfrac{1}{1700}M_{e}

We need to calculate the acceleration due to gravity at the surface of Titania

Using formula of the acceleration due to gravity on earth

g_{e}=\dfrac{GM_{e}}{R_{e}^2}

The acceleration due to gravity on Titania

g_{t}=\dfrac{GM_{t}}{R_{t}^2}

Put the value into the formula

g_{t}=\dfrac{G\times\dfrac{1}{1700}M_{e}}{(\dfrac{1}{8}R_{e})^2}

g_{t}=\dfrac{64}{1700}\times G\dfrac{M_{e}}{R_{e}^2}

g_{t}=0.004705 g_{e}

g_{t}=0.03764\times9.8

g_{t}=0.37\ m/s^2

The acceleration due to gravity at the surface of Titania is 0.37 m/s².

(b). We assume Titania is a sphere

The average density of the earth is 5500 kg/m³.

We need to calculate the average density of Titania

Using formula of density

\rho=\dfrac{m}{V}

\rho_{t}=\dfrac{M_{t}}{\dfrac{4}{3}\pi\times R_{t}^2}

\rho_{t}=\dfrac{\dfrac{M_{e}}{1700}}{\dfrac{4}{3}\pi\times(\dfrac{R_{e}}{8})^2}

\rho_{t}=\dfrac{512}{1700}\times\rho_{e}

\rho_{t}=\dfrac{512}{1700}\times5500

\rho_{t}=1656.47\ kg/m^{3}

The average density of Titania is 1656.47 kg/m³

Hence, (a). The acceleration due to gravity at the surface of Titania is 0.37 m/s².

(b). The average density of Titania is 1656.47 kg/m³

8 0
3 years ago
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